Just a quick question regarding spin and parity. I am studying nuclear physics and I am just a tad confused with a concept about gamma radiation.

Say I have ${^{20}_{10}Ne}$

And the lowest electric multipole of gamma transition between some excited states, such as from 5.00Mev to 4Mev levels is E3.

What is the possible value(s) for the spin and parity of the 4 MeV level, if the 5Mev is $2^-$?

I know since it is an E3 transition then there is is a parity change, since $E_{l_\gamma}=(-1)^{l_\gamma}$

But for the spins, is there not a lot of possible number of values?

Since $l_\gamma = |J_i-J_f|,|J_i-J_f|+1,...,(J_i-J_f)-1,(J_i-J_f)$ and $J_i = 2$ and $l_\gamma = 3$

I think this solves out to be:

It could be $J_f = 1^+,2^+,3^+,4^+,5^+$ ???

This is just an example - but think I could extrapolate from it.


1 Answer 1


You're right that1+, 2+, 3+, 4+, and 5+ are all possible values for the final state following an E3 transition. However, if the final state were 1+,2+, or 3+, then an E1 transition would be possible. If the final state were 4+, then an M2 transition would be possible. So if the lowest multipole is E3, that leaves just one option.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.