Two-part question here, concerning the real-world application of torque.
I have a bolt on my vehicle that I have to tighten to about 200 ft-lbs. But my torque wrench is only calibrated for up to 150 ft-lbs.
If I sheathe the end of my regular ratchet with a 4-foot "cheater pipe", and then hang a 50 lb weight at the end of that 4-foot moment until the bolt stops turning, I believe the torque will then be greater than 200 ft-lbs (because the 4-foot galvanized steel pipe itself has significant weight.)
My two-part question is:
- Is my intuition for accurately simulating a torque wrench correct?
- How might I account for the weight of the (straight, uniform) pipe in a manner that is physically correct? (This seems like possibly an integration problem.)