1
$\begingroup$

Assume two springs with constant $c_1$ and $c_2$ are based in the following scenarios. Figure out the masses for equal displacement.

More specifically I am to figure out what masses $m_1$, $m_2$ will produce equal displacements $x_1$ and $x_2$

Scenario 1: When the two springs are hung from separate supports

Scenario 2: With one spring below the other.

I have never taken physics before and I'm really unsure how to tackle this problem. If anyone can help that will be great.

$\endgroup$

migrated from math.stackexchange.com Feb 9 '15 at 19:44

This question came from our site for people studying math at any level and professionals in related fields.

  • $\begingroup$ are the masses extra bodies attached to the springs or just the mass of the springs? $\endgroup$ – Phoenix87 Feb 9 '15 at 17:26
0
$\begingroup$

I'm not sure I understood the details of the system. If I understood correctly, here is my solution for one of the scenarios you described.enter image description here

$\endgroup$
0
$\begingroup$

Hung separately;

$$M_1g = C_1X_1$$

$$M_2g = C_2X_2$$

Since the displacements are equal therefore we have;

$$M_1g = C_1X_1$$

$$M_2g = C_2X_1$$

Therefore;

$$\frac{M_1g}{C_1} = \frac{M_2g}{C_2}$$

Therefore;

$${M_1} = \frac{M_2C_1}{C_2}$$

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.