I am Computer Science student and learning about quantum computing. But, I have a problem in understanding Bit and Qubit relationship. A bit with 2 bits = 4 states 00,01,10,11--- 1 state at a time. How is Qubit different? Will it also contain 4 states with 2 bits? How will the states get processed paralalley?
Please, ignore my 'novice'ness in this topic but this is hell interesting.
I came across "How are qubits better than classical bit?" but the frequency of this discussion is higher than my frequency.
So, I have gathered something, please rectify me if I am wrong.
The only difference is in their states. So, 2 bits will be 00,01,10,11. For 2 Qubits it will also be same i.e 00,01,10,11.
Will the diagram look like this:
Now, the probability that which state will it enter depends on the superposition of 0 and 1.
This explains: "When the compass needle points north, that is like a qubit being in the state $∣0 \rangle$, and when the compass needle points east, that is like a qubit being in the state $∣1 \rangle$. But a compass needle can also point northeast. The direction northeast is neither north nor east, but it is a superposition of equal parts north and east: if you add a north-pointing vector and an east-pointing vector of equal magnitude, you will get a vector that points northeast. Similarly, the qubit state $\frac{1}{\sqrt{2}}(∣0\rangle+∣1\rangle)$ is neither $∣0 \rangle$ nor $∣1 \rangle$, but it is a superposition of equal parts $∣0 \rangle$ and $∣1 \rangle$." - David
Where am I wrong?