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How do you transform between the electromagnetic tensors $F_{\mu\nu}$ and $F^{\mu\nu}$? $$ F_{\mu \nu}= \begin{pmatrix} 0 & E_x & E_y & E_z \\ -E_x & 0 & -B_z & B_y \\ -E_y & B_z & 0 & -B_x \\ -E_z & -B_y & B_x & 0 \end{pmatrix},\\ \ F^{\mu \nu} = \begin{pmatrix} 0 & -E_x & -E_y & -E_z \\ E_x & 0 & -B_z & B_y \\ E_y & B_z & 0 & -B_x \\ E_z & -B_y & B_x & 0 \end{pmatrix} $$ In other words, what do you do to $F_{\mu\nu}$ to get $F^{\mu\nu}$?

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I see now, as with transforming one-forms to/from vectors, you apply the metric. Because you want to make two subscripts superscripts, apply it twice. So, with $$ g^{\mu\nu} = \begin{pmatrix} 1 & 0 & 0 & 0 \\ 0 & -1 & 0 & 0 \\ 0 & 0 & -1 & 0 \\ 0 & 0 & 0 & -1 \end{pmatrix} $$ $$ F^{\mu\nu} = g^{\mu\nu}F_{\mu\nu}g^{\mu\nu} $$

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  • $\begingroup$ Though a more rigorous explanation would be appreciated $\endgroup$ – CactusHouse Feb 8 '15 at 2:55
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    $\begingroup$ You should write $F^{\mu\nu}=g^{\mu\rho}F_{\rho\sigma}g^{\nu\sigma}$. An index can only appear twice in a factor. $\endgroup$ – Ryan Unger Feb 8 '15 at 3:01
  • $\begingroup$ What "more rigorous explanation" are you looking for? Index raising/lowering is defined with the metric. $\endgroup$ – Quantumness Jun 25 at 18:19

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