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I am interested in the magnetic field attenuation by µ-metal. Specifically shielding from earth's magnetic field $\boldsymbol{H}_E$ through closed cylindrical layers of such a metal, yielding an internal attenuated field $\boldsymbol{H}_A$.

One can buy magnetic shielding from different sources and they all offer seemingly empirical equations$^1$ to calculate the shielding factor $S$ which carries the unit dB (decibel). \begin{equation} S = 20\ \log_{10}\left(\frac{\boldsymbol{H}_A}{\boldsymbol{H}_E}\right) \end{equation} If one has a cylindrical (µ-metal) encased space, the attenuation of a DC magnetic field perpendicular to the cylinder axis is for example given through $S_i$: \begin{equation} S_i = \frac{\mu}{4} - \left(1-\frac{d^2_{\mathrm{inner}}}{d^2_{\mathrm{outer}}}\right) +1\ , \end{equation} where $\mu$ is the magnetic permeability and $\left(d_{\mathrm{outer}}-d_{\mathrm{inner}}\right)/2$ is equal to the wall thickness of the cylinder.

Furthermore they describe the combined shielding factor of a (long) cylindrical two layer shield through $S_{\mathrm{total}}$: \begin{equation} S_{\mathrm{total}} = S_1S_2\left(1-\frac{d^3_2}{d^3_1}\right)+S_1+S_2\ , \end{equation} where $d_1$ and $d_2$ refers to the average (I'm not quite sure about this) diameter of the first and second layer, respectively.

I have searched around and couldn't really find a source or derivation of these equations. All I can find are related to AC fields. Could somebody explain the origin of the last two equations, perhaps there is a paper/publication I've overlooked?

Thanks

[1] http://www.magneticshields.co.uk/en/faq

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It took me a while, but here are the sources for both equations:

  1. http://dx.doi.org/10.1109/TMAG.1970.1066714
  2. http://dx.doi.org/10.1016/0168-9002(86)90989-7

Hope that helps others as well.

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  • $\begingroup$ You are encouraged to answer your own questions, but answers that consist of nothing more than a link(s) to some off-site resource(s) are frowned upon on Stack Exchange site. Reproducing the key ideas here would make this into a good and useful answer. Otherwise it is better suited to a comment. $\endgroup$ – dmckee Jul 3 '15 at 0:08

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