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If air cannot conduct electricity, how can lightning happen?

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    $\begingroup$ see en.wikipedia.org/wiki/Dielectric_strength $\endgroup$ – Phoenix87 Jan 23 '15 at 13:41
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    $\begingroup$ What about Wikipedia's take does not satisfy you? $\endgroup$ – ACuriousMind Jan 23 '15 at 13:44
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    $\begingroup$ In case the air had a significant conductivity, no lightning at all was possible. Charge separation is not possible when you have everything "shorted". $\endgroup$ – Georg Jan 23 '15 at 14:07
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    $\begingroup$ @ACuriousMind The layout of the wikipedia article doesn't readily point someone with that question to its answer. $\endgroup$ – Señor O Jan 23 '15 at 16:02
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    $\begingroup$ Here is an analogy: If I push on a wall very little happens. If I push really hard the wall will break down and stuff will happen (my wife will get mad). At low voltages, air is a good insulator (very little happens), and sufficiently high voltages (well, high field strengths) then air breaks down and stuff happens (sparks fly). $\endgroup$ – copper.hat Jan 24 '15 at 7:37
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This is due to the principle of dielectric breakdown. During thunderstorms, the air between the cloud and the ground acts like a capacitor. When the electric field is high enough, the air partially ionizes, at which point there are free electrons to carry current and the air becomes, essentially, conductive.

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Air does not conduct electricity in the way that metals do. We normally think of conductors as metals with free electrons that move easily throughout the whole metal. Small voltages move the electrons and a current can flow.

In the case of air and many other materials there are electrons present, but they are firmly bound to individual atoms and molecules and cannot move about the way the free electrons do in metals.

Now if we use a very very high voltage - from about 200 V to 1000 V (or higher) mostly - then we can get sparks formed, lightning or other sorts of plasmas where there are free electrons moving in the gas that can conduct electricity. A significant amount of energy is required to generate these plasmas because electrons from atoms and molecules must be removed against large energy barriers. High voltage is required to drive this 'ionization' process in the gas. Have a look at Paschen's Law and note the Paschen curves showing minimum breakdown voltages for different gases. (Note that energy is required to maintain free electrons in a gaseous environment like air, whereas in a metal conductor the free electrons are always present. Every free electron must be generated by ionization of gas atom/molecule or electron emission from a surface - so for every free electron in the plasma there must have been 5 to 10 eV or more energy used to generate the free electron ... and then electrons will be lost, for example in recombination with positive ions, so energy must be continually used to maintain a significant number of free electrons)

So with large voltages it is possible to generate electrons that can move freely in a gas and conduct electricity - as in the example of lightning.

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    $\begingroup$ Sparks can occur with much lower voltages as well, but generally require a decent amount of current instead - if you wish to see an example, try charging up a capacitor and then shorting the leads, or just head over to youtube and see the results $\endgroup$ – user2813274 Jan 23 '15 at 18:48
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    $\begingroup$ Minor gripe: if you opt to use TeX for quantities, format the units or just use plain typesetting; i.e. use either $200\:\mathrm{V}$ or 200 V, but not $200 V$. It looks ugly as it's formatting the V as though it's a variable. $\endgroup$ – Nick T Jan 23 '15 at 22:46
  • $\begingroup$ @NickT - thanks for the comment - text modified and I agree it looks better. $\endgroup$ – tom Jan 24 '15 at 12:29
  • $\begingroup$ @user2813274 - yes you are correct - lower voltages can cause sparks, which is why I put 'mostly' - linked Paschen's law/curves... $\endgroup$ – tom Jan 24 '15 at 12:31
  • $\begingroup$ @tom: I think you mean, A significant a<s>m</s>mount of POTENTIAL energy is required to generate these plasmas? At least fix the double m. $\endgroup$ – cardiff space man Jan 25 '15 at 11:39
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In addition to the other answers, here is a view on the atomic level.

In the molecules of air, the atoms making up the molecules have valence electrons that bind together to form the molecules. The outer shell is initially not full of electrons but will be full when such atoms "share" electrons.

Electrons can have different energy levels - or energy states. Many very close states make up a band. The band where the valence electrons are, when they are bound in the molecule, is called the valence band.

enter image description here

This band is full. No spaces for more electrons. (The exclusion principle forbids two electrons to occupy the same state, so since all states have an electron, the band is full). No electrons can move from one state to another within this band, since no states are empty. (The exclusion principle also explains why usually only the outer shell is important in reactions - the inner shells are full already.)

Now, if one electron can jump up in energy level - all the way up to another band - then in this new band, all the other states are free and unoccupied. This electron can move almost freely around from state to state within this band, and almost no force or energy is needed to move it around. This band is called the conduction band.

If there are electrons in the conduction band, this material can conduct current.

  • Very good conductors have a conduction band and a valence band that almost overlaps.
  • Very good insulators have bands far from each other - there is a large band gap in between.

For electrons to move up to the conduction band in an insulating material, they need to be added enough energy equal to the band gap $E_g$ to move up there. As far as I remember, the energy gap is at about $5 \:\mathrm{eV}$ for a usual insulator to move one electron up there. This is a large amount of energy, that only rarely is applied; e.g. in a thunderstorm where huge potential differences are created.

Then electrons are moved up and "freed" from their fixed positions with the atom. The atoms are now ionized. Then lightning can happen in an insulator like air that suddenly becomes conducting.

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  • $\begingroup$ Do we need a high voltage or also a high potential can ionize air molecules ? $\endgroup$ – ado sar Jun 19 at 20:15
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A lightning/thunder is just an electrical spark (which everyone with electrical background knows how it's done), amplified by 1.000.000 times. So if you lack such a background it's a bit difficult to provide a solid scientific explanation but I'll try.

But before that, it's helpful to resolve some of the misconceptions that your question implies.

  • When it comes to voltage there is really no material known to man that can act as an absolute insulator. This includes stuff like glass, plastic and even air itself. So air, in the absolute sense, DOES conduct electricity just very very poorly and nowhere near as good as metals do.

  • When it comes to high enough voltages then there is no material known (depending on the material) that cannot act as a good conductor. That's what the "dielectric breakdown" is all about. How much voltage can it withstand before it turns into a conductor.

  • A fundamental property of the nature is its desire to restore the equilibrium of any imbalance it encounters. This is true for pretty much everything we know; temperature, pressure and of course electrical charge, which is what sparks and lightnings are all about. And naturally (as with all things) the bigger the imbalance, the more drastic and dramatic (sparks fly) the effect of this restoration.

So in essence, lightning is not caused by electricity per se but rather by the drastic "nullification" of the electrical potential. Putting it simply, it's a gigantic spark that happens in order to quickly restore the balance of electrical charges between two objects (two clouds or one cloud and the ground) that have different amounts of charges.

If you need more scientific information then as Kieran Hunt mentioned, the "Dielectric breakdown" is the next subject to read in order to gain deeper knowledge.

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protected by Qmechanic Mar 14 '16 at 7:22

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