In the radial function for a central potential, if we have a case such that $V(r)$ tends to $0$ much faster than $\frac{1}{r}$, how does $u(r)$ behave? And if $V(r)$ tends to $0$ like $\frac{1}{r}$, what changes in the previous argument? I know that, for $E<0$, it has to be in accordance with hydrogenic wave functions.

  • 2
    $\begingroup$ Could you define things a little bit more clearly, I assume by $u\left( r \right)$ you mean the radial part of the wavefunction? $\endgroup$
    – ChrisM
    Jan 21, 2015 at 16:44
  • $\begingroup$ Yes that's correct. Sorry I'm on my phone haha so a bit lazy to type :/ $\endgroup$
    – Artemisia
    Jan 21, 2015 at 16:56
  • $\begingroup$ think you might find what you are looking for here physics.stackexchange.com/questions/12892/… and links within $\endgroup$
    – ChrisM
    Jan 21, 2015 at 16:58


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