# Electrostatics of Conductor

In an isolated conductor the extra positive or negative charges will be distributed on the surface uniformly. Hence there will be no charge inside the conductor, hence no field. But what accounts for such behaviour of charges? To avoid repulsion? ( from neutral atoms inside, they distribute on surface tolerating repulsions from charges of their own kind? )!!

Also due to the presence of, say, positive charge on surface , will the neutral atoms inside the conductor get polarised? In fig 1 How charges will act when facing polarised ends of their own charge type? Will this happen? I mean polarisation of atoms inside the conductor due to surface charge distribution?

Fig 2 says that when charges are distributed on surface, their field is normal to the surface at that point, directing towards (as in fig2 ) or away from the surface. They dont have any E. component parallel to surface. (How?)

Also,

" Certainly a conducting object that has recently acquired an excess charge has a component of electric field (and electric force) parallel to the surface; it is this component that acts upon the newly acquired excess charge to distribute the excess charge over the surface and establish electrostatic equilibrium. But once reached, there is no longer any parallel component of electric field and no longer any motion of excess charge."

BUT, Isn't it true that a charge send field lines in all directions.

What about the other field lines? Don't they polarize the neutral atoms inside the conductor by exerting electrostatic force of attraction or repulsion?

So, thus formed dipoles also will generate field. So, is it that net field due to all these will become zero inside the conductor? Please explain how field becomes zero inside an isolated charged conductor. And what happens to field lines other than those which are parallel or normal (well, they are components of an oblique field! or something like that!) Don't the field lines extend down inside the conductor?

I will look forward to hearing from you soon. Thank you.

• If you want to calculate the fields of naked charges inside a conductor, you need to make a microscopic model of the metal's positively charged crystal lattice and negatively charged electron sea. As in plasma physics you will find that the naked 1/r field of a free charge will be shielded by an additional exponential decay term, i.e. the effective field of the screened charge will have a Yukawa potential. You can find the model explained here: en.wikipedia.org/wiki/Electric-field_screening Dec 25, 2014 at 13:38
• They say " damping of electric fields caused by the presence of mobile charge carriers" Is it an electrostatic condition? And I want to know about remaining field lines of 'surface charges', where they extend and their effect on atoms inside the conductor. Dec 25, 2014 at 13:50
• Mobile charge carriers are the sea of conduction band electrons in metals or the free charges (positive ions and negative electrons) in plasmas. For an uncharged conductor these charges are in balance. By adding an extra charge to the conductor we force the existing charges to re-arrange themselves. An additional electron will repel the other electrons in its neighborhood, thus leaving a positively charged shell of atoms around it self, and this will effectively shield its electrostatic potential. A positive charge (a missing electron, really), will attract other electrons to fill its place. Dec 25, 2014 at 14:06