This question already has an answer here:
I was thinking about this problem:
How much work is required to hold an object stationary in a gravitational field?
How much energy is required to keep an object stationary in a gravitational field, i.e. how many J/s are required?
and I realized I could not come up with a satisfactory answer.
Let's setup an example to limit our scope: First of all let's consider an mini-copter of mass m=10 kg on earth which uses its' rotor blades to reach altitude of h=1 meter. The work required to get it there is roughly: mgh = 9.82 m/s * 10 kg * 1 m.
Which means we spent 98.2 Joules of energy getting it there. So if this work was done under the time t= 2s the effect of the mini-copter engine would be roughly $mgh/t$ ~ 98.2 Joules / 5s ~ 19.64 watt.
Now, obviously the engine would have to keep on running to keep the quadrocopter at the height of 1m, roughly how much effect would be required?
So this is kind of a high-school level question but I can't seem to wrap my head around it.