1
$\begingroup$

I'm well aware of the formula to calculate tension, however, given a real world situation where you have a closed pulley system. How do you measure the force (i.e., tension) required to pull on the rope in the pulley?

I've thought of buying a portable luggage scale and affixing it onto a point on the rope and pulling the scale in parallel to the rope at a constant speed. This will give me a weight measurement, which I'll then be able to calculate the force from.

This seems like an awful way of measuring something. Can you describe some better ways of measuring, which will help me calculate the force required to pull on this pulley?

What if I wanted to pull on the pulley at a certain speed? How do I go about calculating that?

Improve this question
$\endgroup$

1 Answer 1

Reset to default
2
$\begingroup$

How accurate do you need to be? The problem with these calculations is that massless, frictionless pulleys are usually out of stock at Acme Mail Order.

High school physics will give you the tension in the rope, a different set of high school equations will tell you how much extra tension is needed for a certain acceleration. A rough metric is add 10% for friction losses, but if you need really accurate numbers you will have to do empirical measurements. Natural vs. synthetic fibre rope, weave pattern, pulley diameter and wether they've been greased recently will all affect the outcome.

The accuracy of the luggage scale will be sufficiently low that you can go back to the 10% guideline. Proper strain gauges are readily available in the gram-accurate range, and they won't break as easily. Remember to put a jumper across the gauge if you care about what's on the other end.

Improve this answer
$\endgroup$
2
  • $\begingroup$ I don't need to be too accurate since I'll be over-engineering a device that'll be pulling this rope. Are there possibly better and easier ways to measure the force? $\endgroup$
    – Atlas2k
    Dec 18, 2014 at 15:57
  • $\begingroup$ If you are applying a 5:1 safety factor you can usually ignore friction and pulley mass and just use the normal reduction factors (unless we're talking multiple tons, in which case you should be asking a licensed engineer and not the internet) $\endgroup$
    – paul
    Dec 19, 2014 at 7:49

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.