3
$\begingroup$

One of the several definitions of an affine space goes like this. Let $M$ be an arbitrary set whose elements are called points, let $\mathcal{V}$ be a vector space of dimension $n$, and let $\lambda:\mathcal{M}\times\mathcal{M}\to\mathcal{V}$ have the following properties:

  1. For each $p$ in $M$ and each $\vec{v}$ in $\mathcal{V}$ there is a unique $q$ in $M$ such that $\lambda(p,q)=\vec{v}$

  2. $\lambda(p,p)=\vec{0}$ for each $p$ in $M$

  3. $\lambda(p,r)+\lambda(r,q)=\lambda(p,q)$

For classical and special relativitistic physics, an affine space seems to model the physical facts nicely, but not for general relativity. For the latter, we jump to manifolds with an enormous jump in complexity and variability from one author to another.

My question is this: Where does the definition of affine space fall short? I strongly suspect it is in Axiom 3 above, which is a kind of linearity assumption. Unfortunately, no author seems to tackle the transition; all launch full bore into manifold theory. Could someone provide a reference that does-one which discusses the manifold axioms from the point of view of physical phenomena?

Furthermore, can we truly separate the issue of affine versus nonaffine from that of the metric?

Added Later: Please try to understand what I am asking here. There are many treatments available which cover the formalism, but they merely postulate local coordinates. What I am looking for is a discussion of the physical reason for limiting them to local neighborhoods. If our basic set is affine we can establish global coordinates relative to an arbitrarily chosen origin. Thus, given a vector $\vec{v}$ for instance, we can describe a straight line by $\vec{x}=\vec{x}_0+\vec{v}t$ extending to infinity in both directions. Can we thus describe a straight line in a general manifold? If not, then why not? nn

$\endgroup$
  • 2
    $\begingroup$ $\lambda$ is introduced as $\mathcal{R}\times\mathcal{R}\to\mathcal{V}$, then it becomes $M\times\mathcal{V}\to\mathcal{V}$ in property 1, then it is $M\times(\mathcal{V}?)\to M$ in property 2. $\endgroup$ – user10851 Dec 10 '14 at 0:12
  • 1
    $\begingroup$ for geometric or topological reasons (eg curvature, singularities), distance parallelism and single-valuedness may fail in GR and gauge theories like electromagnetism; see also holonomy and monodromy $\endgroup$ – Christoph Dec 10 '14 at 0:21
  • $\begingroup$ My guess is the intended definition is $\lambda : \mathcal{M} \times \mathcal{M} \to \mathcal {V}$ gets the displacement vector between two points. Then axiom 1 should read "$q$ in $\mathcal{M}$", and axiom 2 should read $\lambda(p, p) = 0$. $\endgroup$ – Nathan Reed Dec 10 '14 at 0:43
  • $\begingroup$ Nathan: True, thanks for pointing out my glitch. Correction made. $\endgroup$ – user59591 Dec 10 '14 at 0:56
  • $\begingroup$ Whoops! And Chris! $\endgroup$ – user59591 Dec 10 '14 at 0:57
1
$\begingroup$

Affine spaces use vectors to model displacements between points. This fails in a curved space because displacements no longer add according to the parallelogram law, so it makes no sense to model them as vectors. It's not so much that any particular one of those axioms fails, as that the whole definition is no longer reasonable.

In a curved space, displacements have to be along curves that live in the space. Vectors play the role of tangents to these curves, i.e. elements of tangent spaces. Each point of the manifold is to be thought of as having its own distinct tangent space, and vectors that live in different tangent spaces can't be added or compared directly to each other. (This is all formalized by the notion of tangent bundle.) In order to work with vectors at different points we have to first parallel-transport them to the same point, a process which is path-dependent in curved space.

Re: "can we truly separate the issue of affine versus nonaffine from that of the metric", I am not sure exactly what you're asking, but if the question is how to distinguish between flat and curved spaces (i.e. affine and nonaffine) by looking at the metric, then we can do that by examining the Riemann tensor, which will be zero in flat spaces even if they are described in a weird curved coordinate system (and therefore have a metric that is not obviously the flat space metric).

| cite | improve this answer | |
$\endgroup$
  • $\begingroup$ Thanks. Your outline of manifold theory is helpful and cogent, but I wonder about your assertion that "the whole definition is no longer reasonable." Here's what motivates my question. If i accept the definition of a manifold at the outset, I am only assured of coordinate mappings "in patches." But my intuition says that each point in physical space (or spacetime) can be associated with a unique point in $R^n$. So apply a nonlinear coordinate system to account for the curvature of the manifold. In other words, why can't one embed in $R^n$? (Not talking about Nash theorems here!) $\endgroup$ – user59591 Dec 10 '14 at 5:00
  • $\begingroup$ @Heaviside: the topology of spacetime might be incompatible with $\mathbb R^n$ $\endgroup$ – Christoph Dec 10 '14 at 15:20
  • $\begingroup$ @Heaviside It's true that a single coordinate patch can cover the entire spacetime in many cases of interest, so you can map the whole thing into $\mathbb{R}^n$. And you can make a "straight line" $x_0 + vt$ in $\mathbb{R}^n$. But this will not in general be a straight line or a geodesic in the spacetime...it will just be some arbitrary coordinate-dependent curve. If the spacetime has intrinsic curvature it's not possible for straight coordinate lines to be geodesics everywhere. So the affine structure on $\mathbb{R}^n$ isn't physically meaningful or useful. $\endgroup$ – Nathan Reed Dec 11 '14 at 5:32
  • $\begingroup$ Thanks, Nathan. So-if I begin with the affine axioms and follow a straight line-how do I determine that there is "intrinsic curvature". Note that we haven't (as yet) the mathematical tools to discuss the Riemann tensor. $\endgroup$ – user59591 Dec 11 '14 at 17:45
  • $\begingroup$ @Heaviside Well, you have to have the metric as that's what lets you talk about physical distances and angles. Without that, you just have an abstract space with no connection to reality. Intrinsic curvature is encoded in the metric; the Riemann tensor is just made from a bunch of derivatives of the metric. $\endgroup$ – Nathan Reed Dec 11 '14 at 18:00
1
$\begingroup$

There are two separate issues here. One is that an affine space is similar to a global coordinate system but without a preferred origin, so this question is similar to "Why can't there be a single coordinate patch?" But also there is the question about what an affine structure does for you and what a metric does for you and why we need a metric and why an affine structure isn't giving us what we need.

Single coordinate patch?

I'll only briefly mention the single coordinate patch. If the global topology is equivalent to $\mathbb{R}^n$ then we don't need more coordinate patches, if it is equivalent to $\mathbb{S}^n$ then we only need two, but a well chosen patch can cover the manifold almost-everywhere in every sense of the word. And it would work well enough if you added enough special rules to describe correlations between curves heading out to infinity. I don't personally see how it helps, but you could make it work if you needed to.

What does an affine structure do for us?

We can put a metric on the single coordinate patch of the vector space (a bilinear form, a very restrictive kind of metric that is consistent with the global linear structure of the vector space), thus getting a metric on the set, without having to have multiple coordinate patches. This structure actually matches the theory of special relativity well, because it can respect different linear paths (linear inherited from the affine structure, i.e. all pairs of points in the path give vectors in the same 1-dimensional subspace) as inertial observers and treat them all equally, and not single out a preferred point or direction.

What does a metric structure do for us?

Single we can treat an affine space as a simple manifold with a particular kind of simple space, using a full manifold theory potentially allows us to do more. And multiple coordinate patches isn't the important part. The important part is to make a metric directly without restrictions that it support a global linear structure. Why? Because general relativity has a new physical insight that has to be incorporated somewhere. The insight is from the observation that all bodies are pulled along at the same rate. For instance a body out rest above the earth is pulled straight towards its center. So no matter their mass then all converge towards the center. This is similar in spirit to a bunch of people at the north pole that set off in different directions in groups leaving every 24 hours. Regardless of the mass of the particular person leaving that day, and regardless of the direction they head out, if they go in a straight-as-possible manner, the group will converge on the south pole.

Since we consider straight-line motion as a natural behavior not requiring further explanantion, then if the paths induced by gravity were explained as straight-lines, straight lines that converge, this can explain why all these different bodies follow the same paths. So all that is needed is to make a sense of straight line paths, and to make them converge. The affine structure can do the former (hence is good for special relativity), but not the latter. For the latter we want to set up a curved metric so the "straight-lines" can converge.

And now I'd like to point out that this curvature reproduces what we often call gravity, but is not what I'd call gravity. The curvature can exist far from gravitational sources and propagates and exists on its own, the curvature a bit later in a place is related to the curvature earlier and nearby and how the curvature varies. Just like electromagnetic fields a bit later in a place is related to the electromagnetic fields earlier and nearby and how the electromagnetic fields vary. (Technically, the curvature is second order and the electromagnetic fields are first order, so you need more variation, but still the same principle applies). Gravity, to me, is about how gravitational sources can change that expression about how the curvature a bit later in a place is related to the curvature earlier and nearby and how the curvature varies. If allows different curvature than otherwise would happen. Just as electromagnetic charges can allow different electromagnetic fields than otherwise would happen.

To summarize this last point, we could have curved spacetime and there would be curved paths in spacetime. And this could work fine to explain and model the empty spacetime between sources. But Einstein's equation is about how different sources can cause curvature to bear different relationships to itself than it otherwise would.

So, that's what a metric does for you

Why do we need a metric?

We want to say that different bodies move along the same paths in spacetime, and we want that motion to be natural, a metric can make those paths natural.

Why can't an affine structure do that?

An affine structure gives a linear type structure, so doesn't naturally make paths converge. We could put additional structure on top to do that, but one we have that, it bears little-to-no relationship to the linear-type structure and we'd never need the linear-type structure. So you can have it, but you'd not need it and end up with a different metric anyway to describe the converging paths. To be fair if you lived in deep space in a very flat region of spacetime far from large gravitational sources, maybe you'd never bother to develop General Relativity because gravity wouldn't be something you were used dealing with. But if your world contains these natural converging paths, you want a theory that naturally makes these converging paths stand out as things that can be seen and predicted.

And that's why an affine structure isn't giving us what we need.

edit to respond to added part about straight lines

Straight lines with proportional tangents in an affine space never intersect. Einstein started with the physical observation that initially "parallel" straight lines can converge towards each other and intersect (for instance when there is a gravitational source between the paths they otherwise would have taken), so he sought a mathematical system that can encode that. Affine spaces are not that system because parallel lines do not intersect

| cite | improve this answer | |
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy