Why does my watch act like a mirror under water? I have a digital watch, rated to go underwater to $100 \rm m$. When it is underwater it can be read normally, up until you reach a certain angle, then suddenly, it becomes almost like a mirror, reflecting all the light that hits it, almost perfectly (you cannot read the digits, the entire surface becomes reflective.) 
I've seen this happen with other waterproof watches too, so I don't think it's unique to mine or the specific model. I'm wondering what causes this? My physics teacher was stumped when I told him about this (we're doing lenses and imaging in physics right now.) I think it has something to do with internal refraction. I haven't been able to measure the angle it becomes reflective accurately, I estimate about 30-40 degrees. Near this critical point, it can be half and half reflective, where only half becomes a mirror, but it's always either reflective or not - never in between being reflective and non-reflective.
 A: What you are observing is total internal reflection.  Snell's law tells you that, for a ray transmitting through a surface $n_{1}\sin\theta_{1} = n_{2}\sin\theta_{2}$, where $\theta$ represents the angle of reflection from the surface, $n$ represents the index of refraction of the substance in question, and the labels 1 and 2 represent the source medium and the destination medium.  
If $n_{1}>n_{2}$, as would be the case for light leaving water ($n\approx 1.33$)and entering the air ($n\approx 1$)inside of your watch, simple algebra will tell you that there is a range of $\theta_{1}$ at which you will find that Snell's law predicts $\sin \theta_{2}>1$.  For this range of angles, since you can't solve for $\theta_{2}$, light cannot be transmitted, and must be reflected.  So the watch looks like a mirror.  In fact, if you flip over, and look at the surface of the water, you will find a portion of the surface of the water looks like a mirror, too!
A: I feel that the explanation for this needs a picture:

On the left is the situation you have outside of the water. When you look at the watch, the light you see was refracted through the glass, so that the internal angle is less than the critical angle (where total internal reflection occurs). On the right you see the situation where you are observing from inside the water. Key difference is that there is a much smaller refractive index mismatch at the first interface (water/glass) so the light travels almost straight; consequently, it is capable of reaching the second interface at an angle greater than the critical angle, and undergoing total internal reflection.
If we assume the refractive index of the three media (top to bottom) to be $n_1$, $n_2$ and $n_3$, then the condition for total internal reflection can be calculated by working backwards:
$$\sin\theta_{2} =\frac{n_3}{n_2}$$ 
for the critical angle at the interface between 2 and 3 (where $\sin\theta_3=1$)
$$\frac{\sin\theta_{1}}{\sin\theta_{2}}=\frac{n_2}{n_1}$$
Substituting, we find the angle $\theta_1$ at which the watch will look like a mirror is given by
$$\sin\theta_1 = \frac{n_3}{n_1}$$
In other words - when $n_1$ (the refractive index of the medium with the observer) is greater than $n_3$ (the refractive index of the medium inside the watch) then it is possible that you cannot see the dial.
This problem has been solved by at least one manufacturer of extreme diving watches, by filling the mechanism with a clear fluid with the same refractive index as the (sapphire) "glass":

source: SINN catalog. The watch in the middle of the image has this technology - the others don't. This has the added advantage of making the watch extremely pressure resistant, since the liquid inside is highly incompressible. The watch is rated for 200 bar (2000 m depth). That's not a depth any human should try to dive to.
