Does a proton oscillating at RF produce an EM field with a -E vector to clarify - FACT:  oscillating charges of sufficient frequency produce a propagating EM field. All communications is based on electron oscillation. 
Question: IF a proton was oscillated at RF would it produce a EM field with -E relative to the E of an EM wave from an electron driven antenna. 
Would the two waves cancel if they met, what effect would a proton induced EM wave have on electronic equipment? 
 A: Yes, an oscillating proton would produce electromagnetic waves. However, for the same driving force, the acceleration of an proton would be smaller than that of an electron by a factor of $m_e/m_p$.
Larmor's formula tells us that the total power radiated by an accelerated charge is proportional to the time average of the square of its acceleration (or the time average of the square of the second derivative of its dipole moment). So the radiated power from the proton would be a factor $(m_{e}/m_{p})^2$ smaller for the same driving force. The field strengths would be smaller by $m_{e}/m_p$.
If a proton and an electron were accelerated using the same Lorentz force - say for simplicity, a sinusoidally varying electric field, then the electromagnetic radiation they produced (i.e. scattered) would be $\pi$ out of phase if considered at the same displacement and at the same instant in time.
If you receive an electromagnetic wave without any other source of information, you cannot tell whether that wave has been produced by an accelerated proton or an accelerated electron.
