1
$\begingroup$

I am not into all the tech details of communication via RF with implant chips (tracking chips) and so would like to ask how the known atmospheric pertubations of shortwave radio affect the distances over which one can closely and continuously track an animal with an implanted chip (e.g. a chip transmitting physiological information).

$\endgroup$
  • $\begingroup$ -in ref. to e.g. RFID tags. I am also thinking in regard to e.g. the scenario proposed by Lawrence Kates United States Patent number: 7634975 (RFID tracking of dogs with methods to induce pain or pleasant vibrations to punish or reward in order to control their behaviour Issue date: Dec 22, 2009 - This method could be used by animal abusers - would there be anyway to prevent such? $\endgroup$ – J Thorsdatter Sep 16 '11 at 15:53
  • $\begingroup$ Would Electrical Engineering be a better home for this question? $\endgroup$ – Qmechanic Feb 27 '17 at 19:05
1
$\begingroup$

I think you are confusing a few different technologies.

GPS only receives signals from the GPS satellites, for this it just needs an external antennae. It isn't going to work with an implanted device in a dog.

Radio directional finding (RDF) transmitters used to track migrating animals broadcast a continuous signal which is followed by simply looking for the direction that the signal is strongest and assuming the animal is in that direction. Again you need an external antenna and more power than GPS (modern tag systems actually find the animals position by GPS and broadcast it by cell phone)

RFID comes in two types, powered and unpowered. If the tag has power it can broadcast a stronger signal or use a smaller antennae and work over 10s of meters. An unpowered RFID tag - like the tags used to 'chip' pets uses power broadcast from the reader and only work over a few cm.

$\endgroup$
  • $\begingroup$ and just for the record, a GPS device can be located anywhere in the world; you might have seen the android version where u can get your friends' location. Where an RFID has serious limitations in terms of range. $\endgroup$ – Vineet Menon Oct 17 '11 at 4:50
  • $\begingroup$ @ Vineet Menon - Whilst a GPS device can locate itself anywhere in the world, the device cannot necessarily be located by a third party unless it actually transmits its position by radio or over a communication network, which will necessarily have variable range and coverage. GPS devices only calculate their position via the GPS satellites, they don't transmit to them. $\endgroup$ – Richard Terrett Oct 17 '11 at 8:00
  • $\begingroup$ precisely, the device should send its location information voluntarily as in an android(phone) over another channel different from the one used by GPS. $\endgroup$ – Vineet Menon Oct 17 '11 at 11:44
0
$\begingroup$

There needs to be more information to answer the question as stated, and it seems to have some misconceptions embedded.

It is highly unlikely that a device IN the dog is receiving GPS signals. "Shortwave radio" is typically though of as running from about 0.5 MHz to 30 MHz, and GPS operates at 1200 and 1500 MHz, so shortwave propagation issues don't generally apply to GPS. GPS receivers need power from somewhere, and implanting batteries in dogs would be unusual. It takes a fair bit of compute power and signal processing to access the GPS signal.

The thing in the dog is likely an RFID implant which knows nothing about where the dog is, but it will send a response when powered by an interrogator. These interactions take place in the near field, so "shortwave propagation" issues don't really apply. Finding the dog becomes an exercise like playing "Hot and Cold" where all you really know is the signal is stronger (closer) or weaker (farther away). This may answer your question.

Now if we are talking about a thing ON a dog, then we have enough power and space for GPS reception, and then we need to know something about the transmitter frequency and modulation (method of encoding the data). The transmission range could be yards, miles, or global depending on method.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.