2
$\begingroup$

How does the Lorentz force work? In the context of a homopolar motor.

I am a year 13 student so please keep your answers simple! I am having trouble understanding the Lorentz force; does the magnetic field affect the electrons or what?

$\endgroup$
3
  • $\begingroup$ lorentz force works as other forces (like gravity). It produces change of state (acceleration) of the partile on which it acts (newton 2nd law). The lorentz force then just describes electromagnetic forces (and not gravity!), which (electromagnetic) forces act on the particle charge and movement (since a moving charge is affected by magnetic field as well) $\endgroup$
    – Nikos M.
    Nov 15, 2014 at 22:00
  • $\begingroup$ No, the magnetic field doesn't "care" of the electrons. It is "aware" of the MAGNETIC field produced by the movement of the electrons. $\endgroup$
    – Sofia
    Nov 16, 2014 at 0:34
  • 1
    $\begingroup$ Zax, would you be so kind as to refine your question? Yes, a magnetic field affects electrons. Now, what specifically about this empirical fact would you like to ask about? $\endgroup$ Nov 16, 2014 at 4:12

2 Answers 2

1
$\begingroup$

In the context of the homopolar motor you can find lots of resources on the Internet: e.g. http://blog.first4magnets.com/what-is-a-homopolar-motor-and-how-does-one-work/

In electromagnetism an EMF can be produced by changing the magnetic flux through a conducting circuit. However you can also produce a "motional EMF" by moving charged particles in a magnetic field, via the Lorentz force.

The Lorentz force is exerted on charged particles (in this case, electrons in the conductors) as they move with respect to a magnetic field. The force is of size $qvBsin\theta$, where $q$ is the charge, $v$ the velocity, $B$ the magnetic field and $\theta$ the angle between the velocity and B-field. It is directed at right angles to the B-field and velocity.

This force can be used to generate an EMF or in the case of a motor where the EMF is supplied, the Lorentz force can be used to move a conductor.

$\endgroup$
2
  • $\begingroup$ Would you mind linking to the 'lots of resources'? $\endgroup$ Nov 17, 2014 at 6:47
  • $\begingroup$ @ZaxPullar I've put in a couple of links. Search engines revealed many more. $\endgroup$
    – ProfRob
    Nov 17, 2014 at 18:19
0
$\begingroup$

Electrons such as all protons, neutrons, positrons, ... have magnetic moment(s). If a electron lay in a magnetic field this field will align this moment, such like every magnetic dipole will be aligned.

Now if the electron is moving into a magnetic field his magnetic dipole will be aligned too. But this alignment is accompanied by a gyroscopic effect. Gyroscopic effect means that every rotating body act again the force which try to align it. Because the electron has not a magnetic moment only but spins too the electron will be deflected. Since any deflection lets to a photon emission and this emission is directed against the gyroscopic effect so the direction of the magnetic moment of the electron more or less fall back in his previous orientation. Now the game starts again. Only the electron due to the photon emission loses energy, the velocity slows down and the path of the electron is a spiral. If to be precise it is a spiral made from "tangerine slices"

$\endgroup$
3
  • $\begingroup$ Not in the least responsive to the question. $\endgroup$ Nov 30, 2014 at 20:21
  • $\begingroup$ @dmckee About the homopolar generator see my answer physics.stackexchange.com/questions/172620/… $\endgroup$ Mar 27, 2015 at 21:49
  • $\begingroup$ @HolgerFiedler:Your answer gives some info about why an electron experience a force in magnetic field.To be honest I still couldn't get why the electron deflects in a magnetic field as said in this video.Could you help me by explaining it a little bit more simple $\endgroup$
    – justin
    May 2, 2016 at 10:36

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.