I am asking a related question here : Newton's Third Law Angular Bouncing
Why, given newton's third law would a ball bounce at an opposite angle to it's original, if an equal and opposite force should push it back through it's original trajectory?
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The force between the ball and the wall is normal to the wall, and therefore its direction is not opposed to the initial motion of the ball but rather to the motion of the ball relative to the wall.
Forgetting for a moment rotation, the velocity of the ball perpendicular to the wall is reversed; the result is that the angle of incidence = angle of reflection (under the assumption of no rotation, no losses, etc...)