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Adiabatic + isothermal = no heat and temperature change. Does that mean the system will remain as it is?

If it is adiabatic + isovolumetric or adiabatic + isobaric , is it as well no change in any variables at all?

Thank you for helping me to clear the confusion.

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If you are considering a single phase single component closed system, what you say would be true, as it only takes two thermodynamic properties to define a single phase single component closed system.

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    $\begingroup$ this is correct if we restrict to reversible transformations, that yield an equation of the form $X=f(T)$, where $X$ is the other macroscopic coordinate. A counterexample is the free expansion of a perfect gas. $\endgroup$
    – pppqqq
    Sep 28, 2014 at 7:53
  • $\begingroup$ This answer would be fine if it was amended by @pppqqq's suggestion. $\endgroup$ Oct 29, 2014 at 3:03

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