To add to Lordrain's answer, I'll give you two scenarios where this equation would be useful. First, notice that this is Maxwell's extension of Ampere's law, meaning you can apply it to situations where a magnetic field exists but there is no current (e.g inside a capacitor with an alternating current). Let's first consider the situation where you'd like to find the magnetic field produced by a current carrying wire. We will take the Amperian loop to be a concentric circle around the wire. We know that:
$$\oint\vec{B}\cdot d\vec{s}= 2\pi rB$$
since the magnetic field is always parallel to the loop (by the right hand rule), and the path length is $2\pi r$ where $r$ is the distance from the wire. We also know that:
$$\mu_0I+\mu_0\epsilon_o\frac{d\Phi_e}{dt} = \mu_0I$$
since there is no displacement current in this situation. This allows us to find an equation for the magnitude of $B$:
$$B=\frac{\mu_0I}{2\pi r}$$
Now let's consider the case of finding the magnetic field inside a capacitor $(r<R)$ with two circular plates or radius $R$, and with an alternating current in the circuit. Taking the same Amperian loop as before, we also have:
$$\oint\vec{B}\cdot d\vec{s}= 2\pi rB$$
However, in this situation, we have:
$$\mu_0I+\mu_0\epsilon_o\frac{d\Phi_e}{dt} = \mu_0\epsilon_o\frac{d\Phi_e}{dt}$$
because we know that there is no current through a capacitor.
If we take $E=E_0 sin(\omega t)$ for an alternating current, we know that $\Phi_E =AE_0 sin(\omega t)=\pi r^2 E_0 cos(\omega t) $ where $A$ is the area of the loop, and $r$ is its radius. Thus, $\frac{d\Phi}{dt}=\omega \pi r^2 E_o cos(\omega t)$, giving:
$$2\pi rB = \mu_0\epsilon_o\frac{d\Phi_e}{dt}= \mu_0\epsilon_o \omega \pi r^2 E_o cos(\omega t)$$
and we obtain the final expression for $B$:
$$B=\frac{1}{2} \mu_0 \epsilon_0 \omega r E_0 cos(\omega t)$$
Notice that in these two cases, the line integral wasn't evaluated mathematically, but rather arguments of symmetry (and a good choice of Amperian loop) were used to reduce it to something easier to work with. Hopefully this gives you an idea of how the Ampere-Maxwell law can be used to find the magnitude of the magnetic field at certain places in different situations.
