A battery of internal resistance 2 Ohms is connected to an external resistance of 10 ohms. The current is .5 A. What is the emf of the battery?
The correct answer is 6.0 V. When I calculated it like a series circuit with 2 resistors I got 6 V for the emf. But I thought the emf did not include the internal resistance, so I calculated it without the internal resistance and got 5.0 V. I was wondering if someone could clarify this for me?