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Consider a block of mass $m$ attached to a spring. Let it oscillate at a frequency $f$. Now each part of the spring is in SHM. so this means a wave is propagating through this spring.bCan this wave be reflected at the fixed end of the spring resulting in the formation of standing waves?

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  • $\begingroup$ Yes, in valvetrains it the reflected wave in the valve spring that cause surge and loss of contact at high rpm. $\endgroup$ Commented May 19, 2013 at 16:23

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Well, the reflection of a wave at the end happens always. One can picture this by imagining the succesive atoms being pushed off the equilibrium position as the wave propagates. Since the endpoint is fixed, it has nowhere to be pushed but the few atoms near it (I am considering idealized linear chain for simplicity) that have already being perturbed will, after having passed through equilibrium again, pass into the opposite direction.

For transversal waves (as those you have on strings of a guitar) this means that the wave perturbation will change from "up" to "down" at the end (and vice versa) while for the longitudinal waves (as those in your spring) there is a change from "compressed" to "streched" (and vice versa).

enter image description here

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  • $\begingroup$ endpoint is fixed? I think that the endpoint is the last atom in the chain. IMO, the gray line is a graphical helper and the 'length' of a body is always changing. $\endgroup$ Commented Aug 17, 2011 at 10:17
  • $\begingroup$ @Helder: you can imagine that there are two more dots at both ends of the line that are held fixed (but since they are fixed, they don't matter anyway...). In any case, the picture makes it clear that normal modes also exist for longitudinal waves which is what OP was after... $\endgroup$
    – Marek
    Commented Aug 17, 2011 at 11:23
  • $\begingroup$ I upvoted the answer because it is clear. But there are no 'rigid-bodys' in the real world. We have atom's aggregated by EM and none of them is 'fixed' (There is no 'anchor' available). $\endgroup$ Commented Aug 17, 2011 at 13:01
  • $\begingroup$ Great pictures. I might add that if you take the original mass on a spring, replace the spring with one whose stiffness is exactly half, put the mass in the middle of the spring instead of the end, and then fasten a string of these units together end to end, you get the case shown in the very first diagram above. You only get standing waves at that frequency; to get travelling waves, you have to go lower down in the pictures and drive the system at a much lower frequency it approximates a continuous medium. $\endgroup$ Commented Aug 17, 2011 at 13:18

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