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If there is a ship going in the sea at 50km/h, and a length of 5m, width of 2m, how do I calculate the ship resistance caused by water viscosity? in other words I want to calculate the drag Force that should be made to overcome the water viscosity. I found this formula

$F=\frac{1}{2} ρv^2A c_d$

but I can't calculate "$c_d$" (drag coefficient)

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  • $\begingroup$ I tried to guess what you meant by the notation, you can correct it in any case. Also, it is always a good idea to specify what your symbols mean when stating an equation. $\endgroup$ – Void Sep 21 '14 at 10:01
  • $\begingroup$ @JustMe - you need to specify the frontal cross-sectional area $A$ below the water line. For selection of the drag coefficient $C_d$ see: engineeringtoolbox.com/drag-coefficient-d_627.html $\endgroup$ – Johannes Sep 21 '14 at 10:28
  • $\begingroup$ Also note that the water viscosity doesn't enter the equation. So you can't claim the ship resistance is caused by the viscosity of the water. $\endgroup$ – Johannes Sep 21 '14 at 10:30
  • $\begingroup$ A Google search for hull drag would be a good place to start doing some research for yourself. Ignore the links related to drag queens in Hull - they are unrelated to ships. $\endgroup$ – John Rennie Sep 21 '14 at 11:06

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