0
$\begingroup$

So in context of Thevenin's and Norton's theorem, can Thevenin voltage $V_{th}$, as in http://en.wikipedia.org/wiki/Thevenin_theorem, ever be negative? I know that $R_{th}$ can be negative, but never thought of $V_{th}$ one until now.

$\endgroup$
1
$\begingroup$

Yes. It depends on how you define the direction of positive voltage in your equivalent voltage source. In other words, if you switch the positions of the "+" and "-" on a typical diagram, the sign of the voltage will switch.

| cite | improve this answer | |
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.