# How does the gluino change the strong force?

Given that the gluino is in the same representation of SU(3) that the gluon and so the same kind of interaction vertexes with quarks, I guess that it could have a role in the strong force. But there are obvious differences: being a fermion, there is no a classical field, and as you can not accumulate fermions in the same state surely its role in the formation of a QCD string field at long distances is minor, but it is still possible to have pairs of gluino/antigluino bubbling out from the vacuum.

So, how is it? How different is the strong force in a meson with QCD from a meson of sQCD? Can sQCD have mesons of spin 1/2? Has sQCD still a coloured string between quark and antiquark, and if so, has it still the same tension that the QCD string? Is there some remarkable difference between QCD meson and baryons and sQCD composites?

You asked about the SUSY QCD bound state spectrum. Due to the gluino it is indeed modified. You can now have the additional gluino states, $\tilde{g}g,\tilde{g}\tilde{g},\tilde{g}q \bar{q},...$.
• Really a spin 1/2 $\bar g q \bar q$ is valid? or do you mean $\bar g \bar g q \bar q$ Sep 13 '14 at 12:17
• No, I meant $\tilde{g}q \bar{q}$. This can be seen using the technique of combining representations of fields known as Young Tableux. I suspect its beyond the scope of the question but in group language a quark and an antiquark make $\bar{3} \otimes 3 = 8 \oplus 1$ and the $8$ can then combine with the $8$ of a gluino to form a singlet. You can however also have $\tilde{g}\tilde{g} \bar{q} q$ (which again can be shown using Young Tableux). Sep 13 '14 at 12:22