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Just hoping for some clarity regarding Hamilton's characteristic function $W$. When we take a time independent Hamiltonian we can separate the Principal function $S$ up into the characteristic function minus $ht$, yes I know it's the Legendre transform but,

\begin{equation} W=S+ht \end{equation}

Meirovitch in his Methods of Analytical Dynamics p 356 gives $h$ as being the Jacobi energy function $h$ as defined in earlier chapters both his and Goldstein's texts.

This is the only time I have seen it being called $h$ rather than the Hamiltonian. I was just wondering if anyone had read through it and perhaps noticed something different in Meirovitch's definition that escapes me. Most authors define these integration constants as the Hamiltonian instead. I know the difference is subtle but it is intriguing as to why he chose $h$ not $H$! Is it just down to how you express the conjugate momenta?

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I) Hamilton's characteristic function $W(q,\alpha)$ is usually only defined for systems without explicit time dependence, cf. Refs. 1 and 2. This means that the Hamiltonian $H(q,p)$ is a constant of motion. The constant of motion is usually the energy of the system, and it is often denoted with the letter $E$. Ref. 1 uses instead the symbol $\alpha_1$, while Ref. 2 uses the letter $h$.

II) For systems without explicit time dependence, the Hamilton–Jacobi (HJ) equation reads

$$ -\frac{\partial S(q,\alpha,t)}{\partial t} ~\stackrel{\text{HJ-eq.}}{=}~ H\left(q,\frac{\partial S(q,\alpha,t)}{\partial q}\right)~=~ \alpha_1.\tag{1} $$

One may therefore view Hamilton's characteristic function $W(q,\alpha)$ as an $\alpha_1 \leftrightarrow t$ Legendre transform of Hamilton's principal function $S(q,\alpha,t)$

$$ W(q,\alpha)~=~S(q,\alpha,t)+\alpha_1 t ~\stackrel{(1)}{=}~ S(q,\alpha,t) - t\frac{\partial S(q,\alpha,t)}{\partial t}. \tag{2} $$

III) The above is an on-shell formulation. There is a similar story off-shell. (The words on-shell and off-shell refer to whether the EOMs are satisfied or not.) Let us for definiteness assume Dirichlet boundary conditions

$$ q(t_i)~=~q_i \quad\text{and}\quad q(t_f)~=~q_f \quad\text{fixed}.\tag{3} $$

Although OP seems fully aware of this, let us stress that Hamilton's principal function $S(q,\alpha,t)$ should not be confused with the (off-shell) action functional

$$ I[q; t_f,t_i]~:=~ \int_{t_i}^{t_f} L(q,\dot{q},t) ~\mathrm{d}t,\tag{4} $$

nor the (Dirichlet) on-shell action function $S(q_f, t_f; q_i, t_i)$. For more information about the relationship and differences between $S(q,\alpha,t)$, $S(q_f, t_f; q_i, t_i)$, and $I[q; t_i,t_f]$, see e.g. my Phys.SE answers here and here.

Let us emphasize for later comparison that in the stationary action principle we restrict to virtual paths with constant and same fixed initial time $t_i$. Similarly for the final time $t_f$.

IV) Similarly, Hamilton's characteristic function $W(q,\alpha)$ should not be confused with the (off-shell) abbreviated action functional $A[q, E]$, nor the (Dirichlet) on-shell abbreviated action function $W(q_f, q_i, E)$. The abbreviated action functional $A[q, E]$ is usually only defined in the case of no explicit time dependence, cf. Refs. 1 and 2. In this case the (Dirichlet) on-shell action function

$$ S(q_f, q_i, T)~=~S(q_f, t_f; q_i, t_i)\tag{5} $$

only depends on the time-difference $T:=t_f-t_i$. One may show that the

$$ \frac{\partial S(q_f, q_i, T)}{\partial T}~=~-E.\tag{6} $$

For a proof of eq. (6), see e.g. my Phys.SE answer here.

The (off-shell) abbreviated action functional $A[q, E]$ can be defined as a energy $\leftrightarrow$ time Legendre-type transformation

$$ A[q; E, t_f, t_i] ~=~ I[q; t_f,t_i] + E (t_f-t_i) \tag{7} $$

of the (off-shell) action functional $I[q; t_f,t_i]$.

In Maupertuis' principle we restrict to virtual paths with constant and same fixed energy $E$ but with free endpoint times $t_i$ and $t_f$. Formula (7) then becomes equal to

$$ A[q; E, t_f, t_i]~=~ \int_{t_i}^{t_f} p\dot{q} ~\mathrm{d}t, \qquad p~:=~\frac{\partial L}{\partial \dot{q}}.\tag{8} $$

As a consequence, the (Dirichlet) on-shell abbreviated action

$$ W(q_f, q_i, E) ~=~ S(q_f, q_i, T) + E T ~\stackrel{(6)}{=}~ S(q_f, q_i, T) - T\frac{\partial S(q_f, q_i, T)}{\partial T} \tag{9} $$

becomes the $E\leftrightarrow T$ Legendre transform of the (Dirichlet) on-shell action function $S(q_f, q_i, T)$.

References:

  1. H. Goldstein, Classical Mechanics.

  2. L. Meirovitch, Methods of Analytical Dynamics.

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  • $\begingroup$ Thanks very much I understand that now! thinking about it, it doesn't make sense to identify the characteristic FUNCTION with the Maupertuis FUNCTIONAL. I think I will need a little time to work through your answer and I will get back if any questions arise! cheers $\endgroup$ – AngusTheMan Sep 3 '14 at 10:25

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