An ideal blackbody absorbs all incident radiation. Josef Stefan found that the intensity $R$ (power per unit area) radiated by an ideal blackbody is given by
$$ R = \sigma T^4 $$
Q1) Since an ideal blackbody absorbs all incident radiation, and if it is in thermal equilibrium, doesn't that mean that $R$ is just whatever the incident intensity of radiation coming in is? So like whatever radiation hits it is what is given off? In other words if I shine a flashlight on an ideal blackbody, and I know that the flashlight gives off 100 W per m$^2$, and my ideal blackbody is a sheet of 3 m$^2$, then the emitted power from the black body is 100*3 = 300 W, or an intensity of 300 W / 3 m$^2$ = 100 W/m$^2$ which is the same as the flash light?
Q2) Does a blackbody mean that the object is black? I understand the keyhole thing where you shine light in a keyhole and its trapped there, making it essentially a blackbody. But what if an actual black object absorbed all incident radiation. That means that 1) it will keep absorbing radiation and getting hotter and hotter forever. or 2) the black object will absorb all incident radiation (we said it was an ideal black body) but then it emits radiation given by the equation above. Does that mean that the color black actually has a frequency of light?