Using bra-ket notation? Am I using Bra-ket notation correctly? I want to define a superposition of the states, $|0\rangle$ and $|1\rangle$. Is it simply?
$|0\rangle + |1\rangle$
I can't find any non-technical information on it. I'm just a hobbyist.
 A: Yes, that is correct.  A more general form of the superposition of the stationary state would be
$$a|0\rangle + b|1\rangle$$ where $a,b$ describes the probability of each state. The state :
$$|0\rangle + |1\rangle$$
assumes that the state $|0\rangle$ and $|1\rangle$ are equally probable.
A: Close, but not quite.  Since quantum mechanics deals in probabilities, it is necessary to "normalize" the state in order to use it in later calculations.  The most general state for the two-state quantum system you're considering would be
\begin{equation}
|\psi\rangle = \alpha\,|0\rangle+\beta\,|1\rangle
\end{equation}
where the quantities $\alpha$ and $\beta$ are NOT probabilities, but are complex numbers which satisfy the "normalization condition"
\begin{equation}
|\alpha|^2+|\beta|^2=1
\end{equation}
In case you are not familiar with it, the notation $|\alpha|^2$ means $\alpha$ times its complex conjugate.
The value of $|\alpha|^2$ is a real number, and is equal to the probability that a measurement of the system will find it the state corresponding to $|0\rangle$.  Similarly, the value of $|\beta|^2$ is equal to the probability that the system will be found in state $|1\rangle$.
