Can you give details of a recent experiment of deflection of light by the Sun?
What is the distance from the surface of the Sun and what is the exact value of the angle of deflection?
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$\begingroup$ this link provides an analysis of light deflection calculations in GR $\endgroup$ – Nikos M. Oct 26 '14 at 13:55
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Have a look at the Wikipedia article on Tests of General Relativity. The most recent measurement quoted there was by a group from the University of Texas. You can find a copy of the paper here.
They measured a deflection of $1.66$ arcseconds $\pm 10\%$, compared to the prediction from General Relativity of $1.75$ arcseconds.
Respond to comment:
The angular deflection of the light at a distance $r$ from an object of mass $M$ is approximately given by:
$$ \theta = \frac{4GM}{c^2r} $$
Put in the mass and radius of the Sun and you'll find $\theta = 8.48 \times 10^{-6}$ radians. Convert this to degrees and multiply by $3,600$ to convert to arcseconds and you'll recover the figure of $1.75$ arcseconds I quoted above.
answered Aug 3 '14 at 10:59
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$\begingroup$ Is there specified the distance from the Sun? I couldn't find it. Should I assume it was just grazing the surface , at 7c from the centre? $\endgroup$ – bobie Aug 3 '14 at 12:23
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1$\begingroup$ @bobie: yes, that's the angular deflection of a ray that just grazes the surface. $\endgroup$ – John Rennie Aug 3 '14 at 14:10
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$\begingroup$ Aren't there any data relative to rays passing at a certain distance from the Sun? Do we know how the angle of deflection varies with distance? $\endgroup$ – bobie Aug 4 '14 at 4:19
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$\begingroup$ @bobie: I've updated my answer to respond to your comment $\endgroup$ – John Rennie Aug 4 '14 at 5:06
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1$\begingroup$ @bobie: the equation I gave is an approximate equation that works when $\theta$ is small. At these small angles the difference between $\theta$ and $\tan\theta$ is negligable. $\endgroup$ – John Rennie Aug 5 '14 at 11:12
