# Why is bandwidth, range of frequencies, important when sending wave signals, such as in radio?

So in wired/wireless networking and radio, signals are sent in form of wave. Then the concept of bandwidth comes in, which is the difference between highest frequency and lowest frequency in a signal. But I do not get why bandwidth determines the maximum information per second that can be sent. If we are able to send signals of any frequency in the bandwidth, then as the number of signals that are of frequencies in an aggregated signal increases, information that can be sent increases without bound.

Is this not possible because when adding some frequency, information in some frequency is necessarily violated? And why does maximum information per second that can be sent depends only on bandwidth, not highest frequency in the aggregated signal?

From a physics perspective, the fundamental reason for this is something called the bandwidth theorem (and also the Fourier limit, bandwidth limit, and even the Heisenberg uncertainty principle). In essence, it says that the bandwidth $\Delta\omega$ of a pulse of signal and its duration $\Delta t$ are related: $$\Delta\omega\,\Delta t\gtrsim 2\pi.$$ A signal with a limited time duration needs more than one frequency to be realizable. (Conversely, you need infinite time to confirm that a signal really is monochromatic.) The bandwidth theorem, which can be proved rigorously for reasonable definitions of the bandwidth and the duration, means that the smaller the time duration is, the larger the bandwidth it requires. It is a direct consequence of a basic fact of Fourier transforms, which is that shorter pulses will have broader support in frequency space.

(This last statement is easy to see. If you have a signal $f(t)$ and you make it longer by a factor $a>1$, so your new signal is $g(t)=f(t/a)$, the new signal's transform is now $$\tilde g(\omega) =\int g(t)e^{i\omega t}\text dt =\int f(t/a)e^{i\omega t}\text dt =a\int f(\tau)e^{ia\omega \tau}\text d\tau =a\tilde f(a\omega),$$ and this now scales the other way, so it's narrower in frequency space.)

More intuitively, the theorem says that it's impossible to have a very short note with a clearly defined pitch. If you try to play a central A, at 440 Hz, for less than, say, 10 milliseconds, then you won't have enough periods to really lock in on the frequency, and what you hear is a broader range of notes.

Suppose your communications protocol consists of sending pulses of light down a fibre, with a fixed time interval $T$ between them, in such a way that sending a pulse means '1' and not sending it means '0'. The rate at which you can transmit information is essentially given by the pulse separation $T$, which you want to be as short as possible. However, you don't want this to be shorter than the duration $\Delta t$ of each pulse, or else the pulses may start triggering the detection of neighbouring pulses. Thus, to increase the capacity of the fibre, you need to use shorter pulses, and this requires a higher bandwidth.

Now, this is probably very much a physics perspective, and the communications protocols used by real-world fibres and radio links are much more complex. Nevertheless, this limitation will always be there, because there will always be an inverse relation between the width of a signal on the frequency and the time domains.

• Beautifully explained Aug 1, 2014 at 7:39

Note: Emilio Pisanty wrote an answer that is probably a better fit for the question and site, but I'm leaving this answer around because I feel it can contribute to an understanding of how this works in practice.

For one thing, you'd need to be able to differentiate between the signals inside the frequency band.

As an example, I'm going to use a Morse code (CW) transmitter. The same principles, however, apply to pretty much all EM transmitters, of which radio forms a subclass; morse code just happens to be a simple example because it is designed as on/full-amplitude and off/zero-amplitude transmissions only.

Naiively, abruptly, turning a signal on or off, like for example in a crude Morse transmitter, creates sidebands to the transmitted frequency. These sidebands are going to interfere with anything else in the vicinity of the intended transmit frequency, and absent deliberate filtering can extend surprisingly far. The extreme case of this would probably be an unfiltered spark-gap transmitter, which was used before we figured out how to generate a continuously oscillating wave, and with which pretty much everyone was interfering with everyone else on radio. (In fact, that's where the term CW or Continuous Wave comes from in radio applications. Having figured out how to maintain a continous, stable oscillation, we were then able to implement more complex modulations like AM, followed by suppressed-carrier modes, each building on the previous either in terms of spectrum efficiency or signal fidelity, sometimes both.)

This "splatter" can be worked around or managed by various tricks, notably "shaping" of the transmitted or modulating signal. For example, PSK31 (a narrow-band digital transmission mode fairly commonly used in amateur radio) deliberately shapes the modulating signal such that phase reversals occur at near zero amplitude, which limits the splatter to what is considered acceptable bandwidths even with filter bandwidths much larger than the signal bandwidth. (PSK31 signals are just a shade over 31 Hz wide, but are often transmitted using plain SSB transmitters with a filter bandwidth of slightly less than 3 kHz; -6 dB at 2.7 kHz is a relatively common filter bandwidth for SSB.) Morse code transmitters may employ a capacitor across the transmitter keying apparatus to help lengthen the time to get to full amplitude; the less sharp signal causes less pronounced sidebands, leading to less interference than would otherwise be the case.

Obviously, the more time that the modulating signal needs to go from zero to full ampltiude (assuming a binary modulation), the less will be the maximum usable transmission speed of the system, because you spend more and more time in your "wait" state. On the other hand, you can group multiple such signals in a narrower range of transmitted frequencies because they are less likely to interfere with each other. The end result is the same because you are basically trading rise time per signal against number of signals within a given bandwidth.

To derive the maximum symbol rate given an acceptable modulating signal bandwidth and a given signal-to-noise ratio, you can turn to the Shannon-Hartley theorem, which establishes the theoretical upper bound. The modulating signal bandwidth is more important than the transmitted signal bandwidth because you clearly don't gain much in terms of symbol rate by moving from having an analog signal modulating a SSB transmitter, to having the same analog signal modulating a wideband FM transmitter, with the same signal-to-noise ratio after demodulation.

• No, by all means, keep this answer around! This is the sort of thing I meant when I said that engineers have different perspectives and that they're more useful in the real world. The bandwidth lime is still there, but our can be really surprising to see the number of forms it can take. Aug 1, 2014 at 10:52