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A loop of wire is put in a changing magnetic field. The magnetic flux through the loop is given by $4t(t+2)$. The loop is connected to a parallel plate capacitor that has a plate separation of 15mm. Determine the electic field between the plates at time $t=3$ s.

Can anyone go through the relevent equations for this question? Thanks

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closed as off-topic by ACuriousMind, Kyle Kanos, Jim, Bernhard, Brandon Enright Jul 29 '14 at 14:06

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$ \mathcal{E} = -{{d\Phi_B} \over dt} = -8t$ (Faraday's law of induction)

$ E = V/d = \mathcal{E}/d = \frac{-8t}{d} = \frac{-8*3}{15\times 10^{-3}} V/m = -1600 V/m$

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  • 2
    $\begingroup$ I thought giving complete solutions to homework questions was discouraged on this site... $\endgroup$ – Floris Jul 29 '14 at 11:59
  • $\begingroup$ @Guo Qianyi thanks.Why is the emf equal to the potential difference $\endgroup$ – user108605 Jul 29 '14 at 12:06
  • $\begingroup$ @Guoqianyi is it because you are assuming no resistance $\endgroup$ – user108605 Jul 29 '14 at 12:20

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