0
$\begingroup$

I am reading this non-linear discrete dynamical system paper. The authors mention the term hyperbolic model. What does that mean?

$\endgroup$
0
$\begingroup$

I suppose it is related to hyperbolic partial differential equations.

$\endgroup$
0
$\begingroup$

Example of a hyperbolic system, the first order wave equation: $ {\partial \underline{U} \over \partial t} + \underline{A} {\partial \underline{U} \over \partial x} = 0$

The term hyperbolic means that:

  • The eigenvalues of the $m \times m$ Jacobian matrix ($\underline A $) are all real
  • There is a corresponding set of $m$ linearly independent eigenvectors

This allows decomposition of the system into a linear combination of these eigenvectors, where the corresponding eigenvalues of $\underline{A}$ give the wave speeds.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.