Bound states in QED I am a beginner in QED and QFT. 
What is known (or expected to be) about bound states in QED? As far as I understand,
in non-relativistic QM electron and positron can form a bound state. Should it be true in QED? Most of the basic text books on QFT I known treat QED with perturbative methods which do not help to study bound states. Is there a literature to read about it?
UPDATE: According to wikipedia, electron and positron form a positronium. It is an unstable particle which can annihilate to two photons. In particular electron and positron cannot form a bound state. But still there is a logical possibility that several electrons and positrons can form a bound state (though probably once one has at least one electron and one positron, they will necessarily annihilate. Is it true?)
On the other hand, if one considers QED with both electrons and muons, then electron and antimuon form muonium. Clearly they cannot annihilate to photons. However
in another article in wikipedia it is claimed that muonium is unstable. Is it due to some effects of QED or due to actual presence of other, say weak, interactions?
 A: Yes, in QED there are bound states. Nobody can forbid us to take the Coulomb potential into account exactly and the rest - by the perturbation theory. In this way they obtain the Lamb shift, for example.
There are different approaches to bound stated in QED: poles of the scattering matrix, Bethe-Salpeter equation, Schwinger approach, Logunov-Tavkhelidze quasi-potential approach, etc.
A: You have to be careful about use of the term bound state in QFT. There is a related notion of resonance, which is a state that looks approximately like a bound state for a while (possibly a long while!) but eventually decays. For example, if you consider the nonrelativistic hydrogen atom, it has bound states corresponding to the electron orbitals (the n,l,m quantum numbers from any first course in QM). However, if you quantize the electric field, the electron is now free to emit a photon and drop down an energy level. As a result, all bound states except the ground state become resonances once you quantize the EM field. This is a general feature when you go from N-particle QM to QFT: because QFT allows particles to spontaneously emit photons (or gluons, Z/W, etc.) with some small but non-zero probability, many states that were bound states in QM become resonances in QFT.
So the articles you are reading that mention positronium or muonium or whatever would be more correct in calling them resonances. They are states that behave approximately like bound states on a short timescale, but because there is a nonzero probability of emitting photons (or other particles) they eventually do, and hence become "unbound".
The book Mathematical Concepts of Quantum Mechanics by Gustafson and Sigal has a very good treatment of resonances and how they come about in QFT. Indeed, most of the second half of the book is devoted to giving a mostly self-contained proof of the aforementioned theorem about bound states of the hydrogen atom. The book is fairly readable and only assumes prior knowledge of basic classical mechanics and EM, as well as some basic properties of the Fourier transform (though these are reviewed).
