Argument for quantum theoretic conformality of $\cal{N}=2$ super-Chern-Simon's theory in $2+1$ dimensions I am using the standard symbols of $V_\mu$ for the gauge field, $\lambda$ for its fermionic superpartner and $F$ and $D$ be scalar fields which make the whole thing a $\cal{N}=2$ vector/gauge superfield in $2+1$ dimensions. 
Then the non-Abelian super-Chern-Simon's lagrangian density would be,
$$Tr[\epsilon^{\mu \nu \rho}(V_\mu \partial_\nu V_\rho - \frac{2}{3}V_\mu V_\nu V_\rho) +i\bar{\lambda_a}\lambda_a - 2FD]$$ 
Clearly this is classically scale invariant.


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*I would like to know of the argument as to why this is also quantum theoretically conformal   (..may be there is some obvious symmetry argument which I am missing..)

*Also is it true or obvious that if the above is perturbed by a $\lambda Tr[\Phi ^4]$ potential then this might flow to a fixed point which is $\cal{N}=3$ ? And then will it still be superconformal ? 
I would like to know of a way of understanding this phenomenon of supersymmetry enhancement by renormalization flow. If someone could point me to some beginner friendly expository reference regarding this. 
 A: The usual argument for why the Chern-Simons action is exactly conformal is that the action is gauge invariant only if the coupling constant, or Chern-Simons level $k$ (which you have not included in your Lagrangian) is integer valued. If the theory was not conformal there would be a non-zero beta-function which would make the coupling depend continuously on the renormalization scale $\Lambda$. But the integer $k$ can not be a continuos function of $\Lambda$, and hence the beta-function has to vanish. This argument doesn't depend on supersymmetry and hence holds equally well for the $\mathcal{N}=2$ case in your question.
As for the extension to $\mathcal{N}=3$: If I remember correctly you need to add two chiral multiplets $Q$ and $\tilde{Q}$ in conjugate representations of the gauge group and with a kinetic term plus a superpotential of the form you give (something like $W = \frac{1}{k} (\tilde{Q}T^aQ) (\tilde{Q}T^aQ)$). By $\mathcal{N}=3$ supersymmetry the coupling is the same as the Chern-Simons level, and hence the theory is again conformal. Unfortunately I don't know of any good reference which gives a general introduction to this theory. For some recent applications of it see eg papers by Gaiotto and Yin (arXiv:0704.3740) and Aharony, Bergman, Jafferis and Maldacena (arXiv:0806.1218). These references also contain discussions about how the $\mathcal{N}=3$ Chern-Simons theory appears as a conformal fixed point starting from $\mathcal{N}=2$ or $3$ Chern-Simons-matter theory or Yang-Mills-Chern-Simons.
