I would like to provide a more thorough answer to this question here
but I realized I don't know enough about angular momentum. If an airplane wheel is rotating at 100 rpm, and the wheel weighs 10kg, with a diameter of 50cm and a uniform mass (approximations applicable to a standard small aircraft), what is the difference in force necessary to bring the plane to 20 degrees of bank as opposed to when the wheels are stopped?
I know that this involves calculating angular momentum, which I have at 5kgm/s per wheel, so 10kgm/s total, I'm just not sure how I would quantify the affect of this angular momentum when trying to bank the aircraft 20 degrees over a course of 5 seconds (replicating first turn in the airport pattern).
I bet the following terms are involved: $\sin(20), 5s, 10kgm/s.$
Not sure if it's relevant, but we can assume the aircraft wheels are suspended 1 meter below the aircraft.