Calculating decibel gain and loss I'm doing a mobile/wireless networking subject and the physics aspect is giving me some trouble. I'm mainly confused about the conversion of dB, dBm and dBW and how to calculate the gain/loss from an input. 
The problem I'm trying to solve is what the resulting power (in milliwatts) is at certain points in a circuit (x and y). I've tried to describe the scenario as best I can (let me know if I need to clear anything or post a picture)
In a circuit a 100mW input receives a 10 dB Gain and continues to point 'x' where it receives a 2 dB Loss. Then it receives another 2 dB Loss on the way to point 'y', where it receives another 2 db Loss.
To simplify it I guess it would look something like 
100mW --> +10 dB --> -2 dB --> Point 'x' --> -2 dB --> -2 dB --> Point 'y'
Any help would be much appreciated, thanks in advance
 A: Decibels measure a ratio of power on a logarithmic scale. The decibel measure of a ratio between powers $P_1$ and $P_2$ is given by $10\log_{10}(P_1/P_2)$.
dBm is an expression of power relative to 1 mW. dBW is similarly the ratio between some amount of power and 1 W.
Remember, dB measure a ratio. dBm or dBW actually specify an amount of power.

100mW --> +10 dB --> -2 dB --> Point 'x' --> -2 dB --> -2 dB --> Point 'y'

100 mW is +20 dBm, because $10\log_{10}(\dfrac{100\ \mathrm{mW}}{1\ \mathrm{mW}})$ is 20.
20 + 10 is 30.
30 - 2 is 28.
28 - 2 is 26.
26 - 2 is 24.
So after all these gains and losses you have +24 dBm.
24 dBm is 251.19 mW because $10^{\frac{24}{10}}$ is 251.19. 

I was able to come up with an answer of ~251 mW by repeatedly using the Power 2 = Power 1 x 10^ (Gain or Loss / 10) formula.

It looks like you got the right answer, but I'm not sure why you had to repeatedly use a complicated formula. After you convert the input power to dBm, it's just additions and subtractions to work out the output power. Then convert back to mW if you want the answer in mW. That's the advantage of working on a log scale: multiplications and divisions turn into additions and subtractions.
