A commonly used generalization of Pauli Operators is the "clock" and "shift" operators summarized here.
Pauli Operators are generators of SU(2). Are these generalized Pauli Operators generators of SU(n)?
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Sign up to join this communityA commonly used generalization of Pauli Operators is the "clock" and "shift" operators summarized here.
Pauli Operators are generators of SU(2). Are these generalized Pauli Operators generators of SU(n)?
Yes, of course they do: J J Sylvester introduced them in 1882, p. 649, for that very purpose. They are a basis of all $n\times n$ matrices, and thus $\mathfrak{su}(n)$, the Lie Algebra of SU(n). A linear combination of them with suitable coefficients, exponentiated, provides all elements of SU(n).
The complete family of n2 independent unitary (but non-Hermitian) independent matrices $$ (\Sigma_1)^k (\Sigma_3)^j =\sum_{m=0}^{n-1} |m+k\rangle \omega^{jm} \langle m| , $$ where $\omega^n=1$, provides a trace-orthogonal basis for $\mathfrak{gl}(n,C)$, known as "nonions" $\mathfrak{gl}(3,C)$, "sedenions" $\mathfrak{gl}(4,C)$, etc...
It should be evident that $\Sigma _ 1 ^n = \Sigma _ 3 ^n = 1\!\!1$, and the braiding relation, $ \Sigma_3 \Sigma _1 = \omega \Sigma_1 \Sigma _3 = e^{2 \pi i / n} \Sigma_1 \Sigma _3$.
Since all indices are defined cyclically mod n, orthogonality follows, $$\mathrm{tr}\Sigma_1^j \Sigma_3^k\Sigma_1^m\Sigma_3^s =\omega^{km} n~\delta_{j+m,0} \delta_{k+s,0}~.$$
This basis, not very popular for its lack of hermiticity, can be systematically connected to the standard Weyl-Cartan Hermitian basis.
For instance, the powers of the basic clock matrix, $\Sigma_3$, comprising the Cartan subalgebra, map to linear combinations of the $h_k^n$ Lie Algebra elements. For n=3 ("nonions") it is easy to demonstrate their mapping to the Gell-Mann matrices and the identity.
More significantly, the n → ∞ limit is particularly transparent in this language, identifying $\mathfrak{gl}(\infty,C)$ with the Lie algebra of Poisson brackets.
Do you mean "generator" in the group sense or the Lie algebra sense?
As a group, the Paulis don't generate SU(2) since the Pauli group is finite. The same is true for the generalized Paulis.
As a Lie algebra, the generalized Paulis generate SU(n) since $\{ \sum_{ij} \alpha_{ij} X^i Z^j : \alpha_{ij} \in \mathbb{R} \}$ consists of all Hermitian matrices.