The propagator of a QFT is known to have a branch cut as a function of the (complex) external momentum. The branch point (as done by, say, Peskin & Schroeder in eqn.7.19 section 7.1) is identified as the root of the argument of the logarithmic piece. Is this not a scheme dependent piece? At least, at the outset it looks so and it is also the same that one gets under dimensional regularization. Is there a general argument to prove that it is scheme independent?

  • 1
    It is not clear what you mean by this... the exact propagator function (along with all other Green functions in QFT) is renormalization scheme independent. Therefore, any singularities such as cuts and poles would also be scheme independent. – QuantumDot Apr 19 '14 at 7:31
  • I agree with your statement. That was why eqn.7.19 in section 7.1 of Peskin & Schroeder confused me. The log[(1-x)m_0^2+...] term that determines the location of branch cut is part of the finite pieces of the subtractions - which are the scheme dependent pieces. My only question was whether there are some general arguments to show that this piece or the location of the branch cuts therein are scheme independent. I have to look at what is suggested below. – MadKal Apr 20 '14 at 15:45
  • Read on below eqn (7.20) in P&S. The threshold is given by the sum of masses of the two particles of the two-particle state, and those (pole) masses are well-defined and scheme independent. – Siva Dec 31 '14 at 0:08

The logs that you get at one loop are scheme independent pretty much like the beta function at one loop is. There is a nice and neat discussion about it on the second volume of Weinberg.

Your Answer

 

By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.

Not the answer you're looking for? Browse other questions tagged or ask your own question.