0
$\begingroup$

I can understand the mechanism of frequency dependant sound absorption by most materials but does the sound attenuation also depends upon the AMPLITUDE(sound pressure or rather loudness/sound intensity)??? I tried some googling but unfortunately could not find any reliable source but my self thinking and intuition tells me that the answer is yes it does does depend on amplitude of the sound wave.

I think one possible mechanism for this amplitude dependent sound absorption may be like this- Most materials (including air) do not follow Hooke's law fully. That is in in simpler terms the restoring force is not proportional to the strain. And as such we can consider sound wave as a strain wave in a medium, the frequency of sound will not be amplitude independent and so hence the sound absorption, as it depends on the frequency and the frequency in turn depending on amplitude, owing to anharmonicity of the medium.

Please correct me if am wrong fully/partially on this as I don't have full self confidence on what I'm thinking is true b'coz sound physics is not my field of expertise like most of you answering here will be experts, I suppose.

THANKS FOR YOUR KIND ATTENTION. Any citation attached will be most appreciated.

FOR ANHARMONICITY CHECK OUT LINK ATTACHED HEREBY- www.answers.com/topic/anharmonicity

$\endgroup$
2
$\begingroup$

You are right. Like any physical process described by linear equations, there are limits. Think of a sound so intense as to crush the cells in a sound absorbing foam, turning it into a hard surface. A reversible version of that foam is one where the bubbles don't get destroyed, they get flattened to the point that the material they are in starts to play a role, instead of the bubble compression.

$\endgroup$
  • $\begingroup$ Thanks for your answer.It has helped me a lot and has made me finally come to a conclusion that sound absorption does depend upon the sound amplitude. $\endgroup$ – user38220 Apr 6 '14 at 21:12
  • $\begingroup$ Very concise, helpful. Nicely put. $\endgroup$ – Todd Jun 29 '16 at 22:16

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.