So I am a teaching assistant for an introductory physics class. One of the problems on this weeks workshops is:
Where is the near point (far point) of an eye for which a contact lens with power of +2.75 (-0.83) diopter is prescribed.
So I know that the power is the inverse of the focal length, so I can find f in the thin lens equation. I'm pretty sure the near point is the image of what someone with the lens would see? So would I plug in 20/25 cm in for object distance (which is roughly near point of the eye) and then solve fir image distance?
And then for far point, I figure I probably just need to take object to infinity and then the image will actually be the power (in m)?