49
$\begingroup$

Sausages universally split parallel to the length of the sausage. Why is that?

enter image description here

Improve this question
$\endgroup$
7
  • 4
    $\begingroup$ The video explains it fairly well. There is greater tension release when the split propagates along the length. $\endgroup$
    – LDC3
    Apr 1, 2014 at 4:49
  • 11
    $\begingroup$ Being cooked too long probably. $\endgroup$
    – MDMoore313
    Apr 1, 2014 at 14:43
  • 2
    $\begingroup$ First use of the fracture tag. $\endgroup$
    – user5402
    Apr 1, 2014 at 18:40
  • 2
    $\begingroup$ In the image in the question, two of the sausages appear to split in a spiral about the length. $\endgroup$
    – einnocent
    Apr 1, 2014 at 22:51
  • 1
    $\begingroup$ You can see how sausages are wrapped here: youtube.com/watch?v=fW-VMGxeRew&t=53 Note how the linker spins the casing, which may contribute to helical stress. $\endgroup$
    – einnocent
    Apr 3, 2014 at 0:58

2 Answers 2

Reset to default
56
$\begingroup$

This behaviour is well explained by Barlow's formula, even though the English Wikipedia article is incomplete in this context. The German version, on the other hand, gives the full picture (which I will quote in the following).

Stresses in a thin-walled cylinder; Source: Wikimedia commons

The walls of a pipe (or a similar cylindric container, say, a sausage) experience two types of stresses: Tangential ($\sigma_{\rm{t}}$) and axial ($\sigma_{\rm{a}}$). For given pressure $p$, diameter $d$ and wall-thickness $s$, the individual stresses can approximately be calculated from $$\sigma_{\rm{t}} = \frac { p \cdot d } { 2 \cdot s }$$ and $$\sigma_{\rm{a}} = \frac { p \cdot d } { 4 \cdot s }.$$ Here, you can directly see that the tangential stress will always be larger, which is why it is likely that cracks in the container/sausage will first form in this direction. In fact, this is why the first formula is often stated on its own, just as it is the case in the English Wikipedia article.

Fun fact: The sausage example is used by many German students as a mnemonic helping to remember which of the stresses is larger. As a result, the formulas are often called "Bockwurstformeln" (sausage formulas).

Edit: In response to the comments below, I will try to summarize some details about the above formulas

  • The formulas do not directly indicate how and where the container will split. Assuming that the tensile strength is identical in all directions, we can see that there will be a greater release of tension when the crack propagates length-wise (See the video posted by JoeHobbit and the comment by LDC3)
  • A real sausage will of course have various imperfections, which is why the crack path will not be straight in practice
Improve this answer
$\endgroup$
10
  • $\begingroup$ Cool ,you learn something new every day :-) A minor clarification, the cracks form normal to the tangential stress so that they reduce the tangential stress as they widen. $\endgroup$
    – John Rennie
    Apr 1, 2014 at 6:52
  • $\begingroup$ of course stating that the guaranteed higher tangential stress causes a break to (almost) always be lengthwise assumes that tensile strength is identical in all directions. $\endgroup$
    – jwenting
    Apr 1, 2014 at 10:52
  • 1
    $\begingroup$ @jwenting: Indeed, there are quite a couple of assumptions behind these formulas... $\endgroup$
    – bigge
    Apr 1, 2014 at 11:01
  • 4
    $\begingroup$ @SethBattin ideal sausage <3 $\endgroup$
    – n00b
    Apr 2, 2014 at 11:40
  • 1
    $\begingroup$ The cylinder is not assumed infinite. Fluid pressure always acts orthogonally to a surface. A cylinder's side is parallel to its axis so doesn't contribute to axial stress. Only the ends can do that, and an infinite cylinder doesn't have ends. $\endgroup$
    – Hugh Allen
    Apr 2, 2014 at 15:33
16
$\begingroup$

I'll have to take a page from my EE background and say it's because of the path of least resistance. If you look at the end of a sausage, there is already tension along that plane, in multiple locations:

enter image description here

A chain is only as strong as its weakest link (see what I did there? :) ), so it's natural for a hot dog/sausage to split along a path that's already strained.

Improve this answer
$\endgroup$
5
  • 2
    $\begingroup$ Very punny. :) $\endgroup$
    – Brian S
    Apr 1, 2014 at 16:17
  • 1
    $\begingroup$ You guys are going to make me split at the seams with laughter. $\endgroup$
    – WernerCD
    Apr 1, 2014 at 22:25
  • 2
    $\begingroup$ That's the wurst joke that I've heard all day. $\endgroup$
    – Patrick Collins
    Apr 2, 2014 at 23:09
  • 1
    $\begingroup$ This appears to be a link-only answer. $\endgroup$
    – Jason C
    Apr 3, 2014 at 5:53
  • 1
    $\begingroup$ @JasonC nice one, I should have brat my A game. $\endgroup$
    – MDMoore313
    Apr 3, 2014 at 12:39

Not the answer you're looking for? Browse other questions tagged or ask your own question.