Firstly, I love this question and I wish that others will provide more insights so I can learn more.
I would classify #1 and #2 as the same underlying substance, unless the system scaling is such that the flows can be affected by quantum behavior in which case #2 and #3 would be the same. The idea behind a coin toss in the first place is that sensitivity to the Initial Conditions (ICs) is high enough (and could be said to be chaotic) so it is useful as a random number. We don't know very well where the variation in the ICs come from, but we generally don't care because the coin flip experiment subjects those ICs to a transformation that produces a psuedorandom number in terms of heads and tails, just like the famous RANDU computer function. RANDU notoriously does not produce a perfect random number (or even a good one), but this same argument applies for the coin flip, although it is chaotic randomness, meaning that the mathematics has a transition to chaos.
Contrast this to a radioactive decay experiment where the outcome is actually random. Let me be clear that I do not understand Quantum Mechanics (QM), and I don't need to. In fact, it seems like I can't make a statement about QM without being corrected by a physicist. Radioactive decay appears to be the collapse of the wave function of a coherent state outside of the nucleus. This is wrong and I don't know why.
I'm fairly sure we will all agree that in the pre-decay state there is a quantifiable probability for the emitted particle to exist outside the nucleus in $1/s$ units, which leads to the decay constant, and combined with the detection efficiency gets the average (or "expected") rate of the counting. No one has ever provided me a sufficient explanation for how QM gives the described result. In a literal interpretation of QM, I think that the particle would simultaneously be both inside the nucleus and flying away in all possible directions and times of decay. Since the $\Delta m$ of the decay, and thus energy of the particle, is a very accurately known number, maybe the uncertainty of the position of the particle is great. It wouldn't matter anyway because the entire point is that we're not predicting the position of individual particles and are, in fact, using the fact that we don't know as an engineering convenience.
A Defined QM Example
Since the question lacks a clear definition of a quantum experiment I will provide one. Take a GM Tube radiation detector with a small dead time compared to the counting time. Establish a counting time based on an expected value of 100 counts, then look at the count and record if it is odd or even. This functionally does the same thing as a heads or tails coin toss.
Now, some purist is going to comment on this and tell me that the evens are more likely in said experiment. Yes, that's right, I calculate one extra even for every $2.7 x 10^{44}$ experiments. So while there is some imperfection in the experiment design, the experiment gives a random outcome in the true sense of randomness.