9
$\begingroup$

After the BICEP2 results, we now know that $n_s = 0.96$ and $r = 0.2$.

From what I understand, this fits extremely well with the basic chaotic inflation model given by $V(\Phi) = \lambda \Phi^4$.

We also know that amplitude of density fluctuations is $\approx 10^{-5}$ and Energy scale of inflation is around $10^{16}$ GeV.

My question: Given also this information, can we now make an educated guess for how many e-foldings happened during inflation ? Or at least a theoretical lower (upper ?) bound ?

PS: I am only referring to inflation of the patch of space that now contains our observable universe, not inflation of Universe as a whole.

$\endgroup$
5
  • $\begingroup$ There is a lower bound of $\sim 60$ e-folds in order for inflation to solve the problems it was supposed to. $\endgroup$
    – Danu
    Mar 18, 2014 at 10:26
  • $\begingroup$ Yes, but that's kind of a lower bound based on homogenity etc. Will all these extra details in hand, can we make a better calculation ? $\endgroup$
    – user42761
    Mar 18, 2014 at 10:31
  • $\begingroup$ @Danu isn't 60 cited as an upper bound? The flatness problem is solved as long as N>37 according to equation 19 in the reference cited in my answer below. $\endgroup$
    – DavePhD
    Mar 19, 2014 at 18:16
  • $\begingroup$ @DavePhD I know from research experience in the field that this is what theoreticians use as a lower bound for what a model must produce in order to be realistically viable. Actually, it's more like a minimum of $\sim 50-55$, but $60$ is considered the standard. $\endgroup$
    – Danu
    Mar 19, 2014 at 18:28
  • $\begingroup$ @Danu OK, I was seeing 60 as the upper bound for observable e-folds (observable in the CMB), rather than total e-folds. $\endgroup$
    – DavePhD
    Apr 19, 2014 at 22:02

1 Answer 1

1
$\begingroup$

$r = 8(1-n_s)-\frac{8}{N_*}$ for monomial potential inflation models, equation 206 of this reference: http://lesgourg.web.cern.ch/lesgourg/Inflation_EPFL.pdf

where $N_*$ is "the number of e-folds between horizon crossing for observables scales and the end of inflation" (basically the observable number of e-folds).

so for $r=0.16$ (the dust-corrected value of the BICEP2 paper) and $n_s = 0.96$

$N_* = 50$

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.