I would like to ask the following:
If an observer travels up or down in an elevator on earth, does he experience a horizontal force due to earth's rotation?
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Sign up to join this communityI would like to ask the following:
If an observer travels up or down in an elevator on earth, does he experience a horizontal force due to earth's rotation?
Surprisingly, the answer is that yes you do, though the effect is very small. To see this consider the following (highly exaggerated) diagram of the lift shaft:
The Earth rotates at a constant angular velocity of one rotation every 24 hours ($\omega = 7.27 \times 10^{-5}$ radians/sec). The tangential velocity of a part of the lift shaft at a distance $r$ from the centre of the Earth is $v_t = r\omega$ so the velocity $v_t$ increases with $r$. This means as you ascend the lift shaft you accelerate in a horizontal direction otherwise you'd be moving at a different speed to the lift.
We can easily calculate the force. Start with $v_t = r\omega$ and differentiate to get the tangential acceleration:
$$ a_t = \frac{dv_t}{dt} = \omega \frac{dr}{dt} $$
And $dr/dt$ is just the vertical speed (call this $u$). The force is just mass times acceleration, so the tangential force is:
$$ F_t = m \omega u $$
I don't know what speed lifts move at, but let's guess a 1 m/sec. My mass is about 70 kg, so when I'm going up in a lift the tangential force is:
$$ F_t = 70 \times 7.27 \times 10^{-5} \times 1 = 0.005N $$
He may experience a Coriolis force, but that is very small in magnitude. I am not sure if you could measure it. The Coriolis force, however, is only experienced by observers in a moving coordinate system when moving relative to the moving frame of reference. As you situate your elevator on earth, we have a rotating coordinate system, that rotates with the earth.