I am Math Grad student with a little bit of interest in physics. Recently i looked into the wikipedia page for Simple Harmonic Motion.

Guess, I am too bad at physics to understand it. Considering me as a layman how would one explain:

  • What a Simple Harmonic motion is? And why does this motion have such an equation $$x(t)= A \cos(\omega{t} + \varphi)$$

associated with it? Can anyone give examples of where S.H.M. is tangible in Nature.


This is all about potential; it is common that a particle movement is described by a following ODE:
$m\ddot{\vec{x}}=-\nabla V(\vec{x})$,

where $V$ is some function; usually one is interested in minima of $V$ (they correspond to some stable equilibrium states). Now, however complex $V$ generally is, its minima locally looks pretty much like some quadratic forms, and so the common assumption that $V(x)=Ax^2$... this makes the last equation simplify to:


with solution in harmonic oscillations.

The common analogy of this is a ball in a paraboloid dish resembling potential shape; it oscillates near the bottom.

  • $\begingroup$ What I always found kind of interesting (but never actually thought any deeper of) is why the potential is always $x^2$ in the nature (i.e. you don't have to go to higher orders when investigating the extrema). Why not $x^4$? $\endgroup$ – Marek Nov 18 '10 at 0:16
  • 2
    $\begingroup$ @Marek: Usually the $x^2$ term is the leading order term in a Taylor expansion around the equilibrium point, so for small displacements, the potential can be approximated as $\sim x^2$. Of course, it is theoretically possible to have a potential in which the second-order coefficient is zero, and in that case you would have to go to higher orders. $\endgroup$ – David Z Nov 18 '10 at 0:21
  • $\begingroup$ @David an example of that situation can be found in the behavior of fluids very near the critical point for a second order phase transition. $\endgroup$ – dmckee Nov 18 '10 at 2:01
  • 1
    $\begingroup$ David Zaslavsky's comment explains why, for instance, a simple pendulum only behaves as a simple harmonic oscillators for small displacements, because for small $x$ only the $x^2$ term is significant. $\endgroup$ – Tim Goodman Nov 18 '10 at 2:47
  • $\begingroup$ @David: sure, I am aware of Taylor expansion. But it doesn't tell you anything about why the second-order coefficient is non-zero. So my question is (if it wasn't clear before): why does Nature prefer to make it non-zero? Or does she (can there be a situation with $x^4$ potential? dmckee hints at this)? @Tim: for pendulum it works because $\cos(x) \sim 1 + {x^2 \over 2}$, so that's simple. But what if I had ball rolling inside a $x^4$ hill? And is such an example artificial or can something similar be found in nature? $\endgroup$ – Marek Nov 18 '10 at 3:33

Simple harmonic motion (SMH) describes the behavior of systems characterized by a equilibrium point and a restoring "force" (in some generalized sense) proportional to the displacement from the equilibrium.

Example system

A simple mechanical system with this behavior is a mass on a spring (which we will consider in one dimension for ease). There is some point where the mass is stable: it can be left alone with no external forces on it and will not accelerate. That's the equilibrium, call it $x_0$. If you move the mass from that point, the spring exerts a restoring force $F = -k(x-x_0)$. Here $k$ is a property of the spring called the "spring constant"; a stiff spring hs a high spring constant and a weak spring has a low value for $k$. Lets consider the special case where $x_0 = 0$ (with no loss of generality, but just to keep the number symbols to a minimum).

So the acceleration of the mass at any point in time is

$$a = \frac{d^2x}{dt^2} = \frac{F}{m} = -\frac{kx}{m} $$

which is a second order linear differential equation, the solutions to which are of the form you exhibit above (where $A$ and $\phi$) take the part of the two constants of integration needed to make the solution agree with an arbitrary set of boundary conditions.

Let's prove it by explicit substitution: $$x(t)=A \cos(\omega t + \varphi )$$

$$v(t) = \frac{d}{dt} x(t) = A \sin(\omega t + \varphi ) \omega $$

$$a(t) = \frac{d}{dt} v(t) = \frac{d^2}{dt^2} x(t) = -A \cos(\omega t + \varphi ) \omega^2 $$ so substituting back in we get $$ -A \cos(\omega t + \varphi ) \omega^2 = \frac{F}{m} = -\frac{k x}{m} = -\frac{k A}{m} \cos(\omega t + \varphi ) $$ which implies that $$ \omega^2 = \frac{k}{m} $$ which relates the spring constant and the mass of the object to the frequency of oscillation.

General discussion

The thing that is important about SHM is that these restoring "forces" linearly proportional to "displacement" (which we allow that there may be generalized meanings for both "force" and "displacement") are very common in the universe. So a great many phenomena may be described this way (and even more may be if we limit ourselves to small perturbations).

  • $\begingroup$ Suppose a mass attached to a spring intially compressed by some distance is released and then at the equilibrium point it suddenly reverses direction without loss of kinetic energy due to let's take elastic collision with another mass following the same path in opposite direction then can motion of both of them still be called simple harmonic motion $\endgroup$ – Hydrous Caperilla Jan 31 '18 at 8:26
  • 1
    $\begingroup$ @HydrousCaperilla It's motion would be confined to a single side of "equilibrium" and it's period would be half that of harmonic motion. We do assign the equivalent problem in introductory quantum classes and it is sometimes called the "half-harmonic well" or something equivalent. $\endgroup$ – dmckee Jan 31 '18 at 17:21

I guess this thread shows everyone has their own tastes when it comes to this topic!

First of all, it's called harmonic motion because sine and cosine are the elementary harmonic functions. Recall that in general a harmonic function is a solution of Laplace's equation (which shows up everywhere in physics), and in we initially study $sin(x+vt)=sin(kx+\omega t)$ since these are the building blocks of solutions of the wave equation. In QM, the principle of superposition (from ODE's) takes on an entirely different, physical meaning.

It's also obvious that the equation of harmonic motion is the projection of $e^{i\omega t}$ onto the real axis, which is a standard trick to derive this equation.

Now an important example of harmonic oscillators in nature are the atoms in a solid. This is basic 1905 Einstein, in 1905 Einstein showed that atoms in a solid can be treated as quantum harmonic oscillators, and that this explains the behavior of specific heat at low temperatures.

Another important example is that the EM field can be considered as three space where each point is a quantum harmonic oscillator. In fact, the EM field is quantized by considering the Fourier components of the field to be creation and inhalation operators for photons of a given frequency $\omega$, which are exactly alike to the raising and lowering operators of the QM harmonic oscillator.

The final standard remark is that almost all small oscillations in nature can be approximated by $F=-kx$, by a Taylor expansion of the force $F(x)$ to first order in $x$.


This echoes some of the other responses, but simple harmonic motion is universal in the following sense. A system displaced from equilibrium will exhibit some force (possibly zero) as a function of the displacement. "Equilibrium" means that if x is the displacement coordinate, then the response force F(x) obeys F(0)=0. So if we Taylor expand F in x we get F(x) = 0 + F'(0)x + F''(0)x^2/2 + ..., where here x can be a multi-coordinate, F vector-valued, with F' a Jacobian, etc. The point is that for small displacements, the linear term is a good approximation (it is nonzero generically, but not always) and the equations take the form d^2x^i/dt^2 = \sum_j (dF^i/dx^j)(0) x^j. This linear system is reducible to copies of simple harmonic motion if we can diagonalize the matrix F'(0) (e.g., if the force is conservative this is symmetric, a Hessian, and therefore diagonalizable). This same reasoning works in infinite dimensions, formally, so in quantum field theory. If you want an everyday example, kick a wall. It will shake. This is why.


Simple harmonic motions are designated by that name because the time dependence of the coordinate being described is given by a constant multiple of a sine or cosine function of a multiple of the time, i.e., a harmonic function in the sense of being the kind of function employed in the harmonic, or Fourier analysis of a periodic, but otherwise arbitrary motion in terms of sinusoidal functions.

The importance of simple harmonic motion stems, first of all, from its pervasive presence throughout macroscopic nature as the characteristic response to small disturbances from equilibrium which produce restoring forces proportional to the disturbance. Beyond that, and as indicated in the previous paragraph, almost all varieties of motion are analyzable as superpositions of simple harmonic motions of varying frequencies and amplitudes. Such analysis is just what we call Fourier analysis of the motion.

  • $\begingroup$ Nice way to bring in the Fourier superposition bit. I'd been trying to figure a natural way to describe it. $\endgroup$ – dmckee Nov 17 '10 at 22:37

alt text

Consider a particle in circular motion with angular velocity $\omega$ and radius of the circle $A$.

Projection of the particle on diagonal of the circle is in SHM.

Suppose the diagonal of the circle is on X-axis and center of the circle is $(0,0)$.

It is easy to see that equation of position of the projection at time $t$ is

$\phi$ angle at time $t=0$

$x(t) = Acos(\omega t + \phi)$


Anywhere there is a restoring force which is linear with some kind of pertrubation from equilibrium, harmonic motion occurs. Most dynamic systems ehibiting either elastic forces, or some kind of conservative field (like gravity) have a tendency to exhibit harmonic motion. I guess you can view it as the natural dance of potential and kinetic energy.

An example we used in high school was a cork floating on the surface of water vertically. Starting from the position where all is in equilibrium, a small dip of the cork increases the boyancy linearly, and a small rise of the cork decreases. Since the sum of the forces are zero at equilibrium then changes in boyancy are viewed as an additional opposing force to motion that is linear.

A practical application is the measurement of mass moment of inertia of an axisymmetric shape. You suspend the shape from a thin elastic wire and twist it slightly. The resulting oscilation back and forth is S.H.M. and its period is used to calculate what the MMOI around the axis of rotation is. There are companies out there that part of quality assurance for manufactured parts, they run samples through this "simple" test to check the expected performance in the field.


I was once trying to push a large log off a hiking trail trail. The log had been there a while and had sunk into the dirt, so to push it out I would have to push hard enough to force it up out of the depression. I kicked at it, but couldn't kick it hard enough to get it out. I was with a couple other people, so we all kicked it, but again we couldn't get it out. What did happen was that it rolled up a little way out of its hole, then rolled back towards us and climbed a small way out of its hole in the opposite direction. Finally it rolled back the way we originally kicked it again.

We soon caught on to the idea of kicking the log, waiting for it to roll back towards us, then roll the other way, and kick it again while it was already rolling the direction we wanted it to go. With a little effort, this strategy finally let us roll the log out of its depression and off to the side of the trail.

The log was exhibiting simple harmonic motion - it shook back and forth at a certain frequency, oscillating around the spot it would stay at rest. Our kicks were timed to coincide with the period of the log's oscillations. This is called achieving "resonance".

The log was not a perfect simple harmonic oscillator because it would only shake back and forth a few times before settling down again. Ideally, a simple harmonic oscillator will shake back and forth indefinitely. Further, it can shake more or less vigorously (different amplitude of the sine wave), but it will always have the same period and move sinusoidally.

Many mechanical systems are close to simple harmonic oscillators. A pendulum in a clock is a good example. If you take a rectangular or vertical cylindrical ice cube floating in water and tap it very gently, it will oscillate up and down in harmonic motion with a period of around a half a second. The water itself is a harmonic oscillator, too. If you give it a short shove across the table, you'll see the entire surface of the water shake back and forth in a characteristic way called the "sloshing mode". Electrical circuits with an inductor and a capacitor make extremely good simple harmonic oscillators. A quartz crystal is a good one, too. Since it oscillates with a definite period, it makes for a good clock. Older clocks use a different simple harmonic oscillator, a wound up spring that shakes back and forth. If a roller coaster were to roll back and forth at the bottom of a hill, it would be a simple harmonic oscillator, too. If you dug a hole from the north pole to the south pole and dropped something in, gravity would swing it back and forth through the Earth in simple harmonic oscillation.

Simple harmonic oscillators can be used to describe molecular or atomic systems. You can discover a lot about the way that light interacts with matter simply by pretending that an electron attached to an atom is a simple harmonic oscillator, and molecules like CO2 vibrate like simple harmonic oscillators as well. Even you are a simple harmonic oscillator. Spread your feet, make yourself rigid, and rock back and forth from foot to foot, staying stiff so that the foot not supporting your weight actually comes off the ground. You'll find that as long as you don't go too far, there's a certain frequency that your body wants to rock at, and that this frequency changes when you change the distance between your feet.

There are many caveats to all this. These systems are subject to friction, so they run down eventually, unlike an ideal simple harmonic oscillator. Most of them are simple harmonic oscillators only for small amplitudes. If you push the entire ice cube under water, it doesn't obey a sine wave oscillation any more. The roller coaster, even if frictionless, is only a simple harmonic oscillator if the shape of the track is a special shape called a brachistochrone. The hole through the Earth only results in simple harmonic motion under the false assumption that the density of Earth is constant.

Nonetheless, these models are extremely useful at explaining natural phenomena. A large body of water like a lake or bay is a simple harmonic oscillator in the same way as the glass of water pushed across the table to excite the sloshing mode. But the period of the sloshing mode gets longer and longer as the body of water gets bigger. For the Bay of Fundy, the sloshing mode is very close to twelve hours. Since the tides come once every twelve hours, the tides act in a way very similar to the way my friends and I kicked the heavy log out of its hole. The tides build up very strongly, and tides there can be ten meters!

Engineers will have to worry about this resonance phenomenon all the time. The most famous example is the Tacoma Narrows suspension bridge, which started shaking wildly and finally collapsed on a windy day when the turbulent eddies of the wind were in resonance with the bridge. If you're building a building, you don't want it to undergo simple harmonic motion at the same frequency as earthquake waves, and you don't want the suspension on a car to have the same frequency as some sort of regular dip in the road, for example.


A particle excetuing simple harmonic motion should be, periodic its motion must be to n fro n the restoring force should always be directly propotional to displacement in th opposite direction i.e RF`directly propotional to negetive of displacemnt..


protected by Qmechanic Sep 24 '15 at 7:37

Thank you for your interest in this question. Because it has attracted low-quality or spam answers that had to be removed, posting an answer now requires 10 reputation on this site (the association bonus does not count).

Would you like to answer one of these unanswered questions instead?

Not the answer you're looking for? Browse other questions tagged or ask your own question.