I don't really understand horizontal projectile motion. Suppose I throw a ball horizontally. Given $\theta$ = 0 degrees, time = 0.5 seconds, horizontal range = 15.5 metres,
the "initial horizontal velocity of the ball" would just be the average velocity which is displacement divided by time? Or is it $V\sin\theta$?
Also, what would the "final velocity" be? It would be $\sqrt{V_x^2 + V_y^2}$ using the final values since $\theta$ changes?
And would I say that the maximum height reached by the ball is 0 metres or -1.2 metres?
Finally, in order for me to calculate Kinetic Energy, Work, Force, would I need to measure the mass of the ball or can I get the mass using the information I already know such as velocity and displacement and time?