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Why work is equal to $-VdP$ when volume is constant? Doesn't that imply that work is equal to 0? Isn't work a result of volume change?

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  • $\begingroup$ The volume is the volume and is a (non-zero) constant. The pressure changes, so $dP$ is a non-zero number. The product $VdP$ is non-zero. $\endgroup$
    – Jon Custer
    Commented Dec 14, 2023 at 17:46
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    $\begingroup$ Does this answer your question? Questions about flow work/flow energy? $\endgroup$
    – Chemomechanics
    Commented Dec 14, 2023 at 19:02

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The original statement is incorrect. At constant volume, $$dU=dH-VdP$$

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