The Einstein relation says that the diffusion coefficient $D$ and it's mobility $\mu$ under a force are related to each other as follows:
$$ D = \mu k_B T $$
I don't completely understand the derivation to this equation and what are the assumptions that went into deriving this relationship? In the case of an ideal gas, the self diffusion coefficient is given by
$$ D = \frac{3}{8} \frac{1}{nd^2}(\frac{k_B T}{\pi m})^{1/2}$$
This is also applicable in the case of a charged weakly ionized gas and $D$ can be seen as the diffusion coefficient for the ions through the neutral molecules. Would it be correct to use the Einstein relation in this case to obtain the ion mobility through the gas such that:
$$ \mu = \frac{3}{8} \frac{1}{nd^2}(\frac{1}{\pi m k_B T})^{1/2}$$
giving us:
$$ v_d = \mu F = \mu qE = \frac{3}{8} \frac{qE}{nd^2}(\frac{1}{\pi m k_B T})^{1/2}$$
Where $q$ is the charge on the ion.