We did this experiment using Michelson Interferometer of monochromatic source $\lambda$ to find the refractive index $n$ of dry air in a chamber of length $L$ by counting the number of fringes moved radially outwards as the pressure in the chamber decreases.
I am struggling to explain why do the fringes move outward when the pressure in the chamber decreases (We started from 290 torr and stopped at 120 torr).
This is my argument: As the pressure decreases, the refractive index is supposed to decrease (as $n \propto p$ for air $\approx$ ideal gas). This should reduce the path difference $2(n-1)L$ between the two interfering beams. The path difference between the incident and reflected beams is $2d\cos\theta$. $\theta$ is the angular separation of our fringe from the center. $2d$ is the mirror displacement but for our concern $2d = 2(n-1)L$ and thus we have the relation between $n$ and $\theta$ as $P.D. = 2L(n-1)\cos\theta$
For a bright fringe, $m\lambda = 2L(n-1)\cos\theta$. So for a given fringe, m is fixed and hence P.D is fixed. As $n$ decreases, $\cos\theta$ should increase in a way to keep P.D. constant.
But according to my argument, $\theta$ should decrease. That means I am wrong somewhere. But where?