For conductors, we propose that the free current density is proportional to the applied Electric field and the constant of proportionality is defined as conductivity.
\begin{equation} \textbf{J}_\textbf{f} = \sigma\,\textbf{E} \end{equation}
Maxwell's equation in the conducting material (assuming linear media) take the form, \begin{equation} \vec{\nabla} \cdot \textbf{E} = \frac{\rho_{f}}{\epsilon} \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\; \vec{\nabla} \cdot \textbf{B} = 0 \end{equation}
\begin{equation} \vec{\nabla} \times \textbf{E} = -\partial_t \,\textbf{B} \;\;\;\;\;\;\;\;\;\;\ \vec{\nabla} \times \textbf{B} = \mu\sigma \,\textbf{E} \,+ \mu\epsilon \, \partial_t \,\textbf{E} \end{equation}
Taking the divergence of the $\vec{\nabla} \times \textbf{B}$ equation and substituting divergence of the electric field with charge density gives,
\begin{equation} \frac{\partial\rho_f}{\partial t} = - \frac{\sigma}{\epsilon}\rho_f \implies \rho_f =\rho_f(0) \exp(-\frac{\sigma}{\epsilon} \;t) \end{equation}
I don't understand what this equation is supposed to mean. If I take some conducting wire and connect it to two ends of a battery the wire still retains its free charges. So how can $\rho_f$ be an exponentially decreasing function of time?