The principle of least action says that a body moves in such a way that the action value $S=\int L dt$ is stationary (often minimal). The principle is written as $$\delta S =0 \ .$$
In contrast, Schwinger's quantum action principle between an in and an out state is $$ \langle{\rm out}| \delta S |{\rm in}\rangle = \frac{\hbar}{i} \delta \langle {\rm out}|{\rm in}\rangle \ .$$ I have a simple question: what is minimized in this case? Or, more generally: what does the principle state, if only words are used? That would be my question 1.
Question 2. Least action implies that the actual trajectory is special: it differs from all the others, because it has minimal/stationary action. In what sense does Schwinger's principle make the actual state evolution special from all the others?
Answering a similar, older question, Qmechanic had written:
Schwinger's quantum action principle is not a variational principle in the sense of finding stationary points for a functional. Rather it gives a formula for how a quantum system (typically an overlap/transition amplitude ⟨𝐴|𝐵⟩) changes under a change of external parameters/sources in the action 𝑆.
Can one add a few sentences to complete the answer to question 2? In what sense is the quantum motion special? How does it apply to free particles? Or: how can one express the quantum action principle for free particles in words?
Question 3. How does Schwinger's action principle become the least action principle in the classical limit? Ok, if $\hbar$ is zero, the two equations are very similar. Is that the way the transition is made? What can be said to make it clearer?
Question 4. The right hand side of Schwinger's principle is $-i\hbar$ times a complex number with a magnitude equal or smaller than one. Why does it enter the principle? Is it correct to say that for long times, the overlap is small, and thus the right hand side is zero?